The relative frequencies, from least to greatest, would be:
The percentage of all entries painted by Art 1 students (14.33%), the percentage of Art 2 entries that were digital (22.02%), and the percentage of clay entries done by Art 3 students (25.32%).
Explanation
The percentage of clay entries done by Art 3 students: There are 20 clay entries done by Art 3 students, out of 79 clay entries; 20/79 = 25.32%
The percentage of all entries painted by Art 1 students: There are 43 entries painted by Art 1 students out of 300 total; 43/300 = 14.33%
The percentage of Art 2 entries that are digital: There are 24 Art 2 digital entries out of 109 total Art 2 entries; 24/109 = 22.02%
We would have two circles of 5cm diameter each, and a rectangle of the length pi*diameter and 2cm, so lets add them:
total = 2circles + rectangle
total = 2(2*pi*(5/2)^2) + pi*diameter*heigth
= 4*pi*(2.5)^2 + pi*5*2
= 109.9
that is the surface area of a bar soap 109.9 cm^2
6i/ (1+i)
multiply by the complex conjugate (1-i)/(1-i)
6i/(1+i) * (1-i)/(1-i)
6i* (1-i) = 6i - 6i^2 = 6i - 6(-1) = 6i +6
(1+i)*(1-i)= 1-i +i -i^2 = 1 -i+i -(-1) = 1+1=2
(6+6i)/2
3+3i
Answer: 3+3i
Answer: There are 3 quarts of concentrate and 9 quarts of water.
Step-by-step explanation:
Since we have given that
Ratio of number of quarts of water to number of quarts of concentrate is
3:1
Number of quarts of orange juice from concentrate and water = 12 quarts
So, the number of quarts of concentrate would be
the number of quarts of water would be
Hence, there are 3 quarts of concentrate and 9 quarts of water.
If every 5 mins, A makes 1 yo-yo every 10 mins, B makes 1 yo-yo then every 10 mins, both machines produce 3 yo-yos every 10 mins (2 from machine A and 1 from machine B) Therefore, for 20 yo-yos, both machines would take 70 minutes( 1 hour and 10 mins). After 70 minutes, 21 yo-yos would be produced.
