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joja [24]
2 years ago
12

What is the product and simplest form 2/3 times 1/8

Mathematics
2 answers:
ludmilkaskok [199]2 years ago
7 0

Answer:

\frac{1}{12}

Step-by-step explanation:

Since we're finding the product, we have to multiply:

\frac{2}{3} × \frac{1}{8}

You can simplify in this stage by using the "butterfly method", and dividing 2 by 2, and 8 by 2, you'd then have:

\frac{1}{3} × \frac{1}{4}

Multiply the numerators and the denominators to get:

\frac{1}{12}

~

If you prefer the longer way, again, multiply:

\frac{2}{3} × \frac{1}{8}

Multiply the numerators and the denominators:

\frac{2}{24}

Simplify the fraction by dividing both the numerator and denominator by 2:

\frac{1}{12}

Morgarella [4.7K]2 years ago
7 0
2/3 multiplied by 1/8 would be 2/24. But in simplest form, it would be 1/12.
This is because when you multiply the numerators (top of the fraction), which in this case is 2 and 1, you get 2.
And the denominators (bottom part of the fraction), which is 3 and 8, would equal 24.
Then that would give you the fraction 2/24. And that can be simplified by finding the gcf (greatest common factors).
The gcf of 2 would be 2. Since it’s the highest number that fits in it.
Since you can’t get any higher than 2, you can’t use any other factors from 24.
So 24 divided by 2 is 12.
So the answer you get in the end is 1/12. I hope this helped :)
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A box of buttons contains the same number of each type of button. It contains 220g of buttons
ra1l [238]

Answer:

a) 18 button a buttons are required to fill the bag.

b) 12 button b buttons are required to fill the bag.

c) There are 11 buttons of each type in the box containing 220 g of buttons.

Step-by-step explanation:

Complete Question

Two button types, button a weighing 8 grams and button b weighing 12 grams. The buttons are sold in bags. Each bag contains 144 grams of buttons.

a) How many of button a are needed to fill one bag?

b) How many of button b are needed to fill one bag?

c) A box of buttons contains the same number of each type of button it contains 220g of buttons. How many of each type of button are in the box.

Solution

a) A bag contains 144 grams of buttons.

Button a weighs 8 grams per button.

Total number of button a buttons required to fill up the bag = (144/8) = 18 button a buttons.

b) A bag contains 144 grams of buttons.

Button b weighs 12 grams per button.

Total number of button b buttons required to fill up the bag = (144/12) = 12 button a buttons.

c) A box of buttons weighing 220 g contains the same number of each type of button.

Let this number be n.

This means the Total weight of button a buttons in this box = 8n

total weight of button b buttons in this box = 12n

Sum total of the weight of the buttons = 8n + 12n = 20n

20n = 220

n = (220/20) = 11.

This means there are 11 buttons of each type in the box containing 220 g of buttons.

Hope this Helps!!!

6 0
2 years ago
Six neighbors share 4 pies equally how much of a pie does each neighbor get
salantis [7]
Divide 4 by 6. Easier if you write it as a fraction: 4/6 This can be reduced to 2/3.   This means that each person gets 2/3 of a pie equally.
8 0
2 years ago
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On a coordinate plane, a curved line begins at point (negative 2, negative 3), crosses the y-axis at (0, negative .25), and the
shepuryov [24]

Answer:

Option D

Step-by-step explanation:

correct answer on edge :)

7 0
2 years ago
The hospital shop buys cereal bars in boxes of 4.
Korolek [52]
First, you divide 58 bars by 4. The answer will be 14 boxes with 2 bars remaining in the box.
8 0
2 years ago
The Fortune 500 is comprised of Fortune magazine's annual list of the finite population of the top 500 companies in the U.S. ran
Serjik [45]

Answer:

The standard error of the proportion is 0.0367.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the standard error is s = \sqrt{\frac{p(1-p)}{n}}

In this question:

p = 0.16, n = 100

So

s = \sqrt{\frac{0.16*0.84}{100}} = 0.0367

The standard error of the proportion is 0.0367.

4 0
1 year ago
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