Twenty percent of what number is equal to five percent of 680
1 answer:
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Answer:
When x = 15, y= 2
When y= 10, x= 3
Step-by-step explanation:
This is a question in inverse proportion. In this proportion, an increase in one quantity would lead to a decrease in the other and vice versa.
We are to complete the table using the relationship between x and y.
Given:
y is inversely proportional to x = y ∝ 1/x
∝ = proportional to
y ∝ 1/x
y = k × 1/x
Where k = constant of proportionality
To understand the relationship between y and x, we need to find the value of k.
y = k × 1/x
From the table,
When x = 6, y = 5
5 = k × 1/6
5 = k/6
k = 6×5 = 30
y = 30 × 1/x
y = 30/x
The above relationship would enable us find the missing parts.
When x = 15, y= ?
y = 30/15
y = 2
When y= 10, x= ?
10 = 30/x
10x = 30
x = 30/10
x= 3
Answer:
The confidence interval for the difference in proportions is
No. As the 95% CI include both negative and positive values, no proportion is significantly different from the other to conclude there is a difference between them.
Step-by-step explanation:
We have to construct a confidence interval for the difference of proportions.
The difference in the sample proportions is:
The estimated standard error is:
The z-value for a 95% confidence interval is z=1.96.
Then, the lower and upper bounds are:
The confidence interval for the difference in proportions is
<em>Can it be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group?</em>
No. It can not be concluded that there is a difference in the proportion of drivers who wear a seat belt at all times based on age group, as the confidence interval include both positive and negative values.
This means that we are not confident that the actual difference of proportions is positive or negative. No proportion is significantly different from the other to conclude there is a difference.