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AlladinOne [14]

1 year ago

15

The price of your service plan before taxes is 89.99. For your convenience, I will deduct 15% off your service plan before taxes

. The price you will pay after the discount has been applied and prior to taxes being added is?

1 answer:

Citrus2011 [14]1 year ago

5 0

First, you must find how much $ the discount takes off
89.99 * .15
=13.4985

Subtract that from 89.99

=76.4915

If you estimate it,
$ 76.49

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C. 0.3012

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that an adult has a landline at his residence.

B is the probability that an adult has a cell phone.

C is the probability that a mean is neither of those.

We have that:

$A = a + (A \cap B)$

In which a is the probability that an adult has a landline but not a cell phone and $A \cap B$ is the probability that an adult has both of these things.

By the same logic, we have that:

$B = b + (A \cap B)$

The sum of all the subsets is 1:

$a + b + (A \cap B) + C = 1$

2% of adults have neither a cell phone nor a landline.

This means that $C = 0.02$ .

73% of adults have a landline at their residence (event A); 83% have a cell phone (event B)

So $A = 0.73, B = 0.83$ .

What is the probability that an adult selected at random has both a landline and a cell phone?

This is $A \cap B$ .

We have that $A = 0.73$ . So

$A = a + (A \cap B)$

$a = 0.73 - (A \cap B)$

By the same logic, we have that:

$b = 0.83 - (A \cap B)$ .

So

$a + b + (A \cap B) + C = 1$

$0.73 - (A \cap B) + 0.83 - (A \cap B) + (A \cap B) + 0.02 = 1$

$(A \cap B) = 0.75 + 0.83 - 1 = 0.58$

So the answer for question 3 is A.

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83% of the adults have a cellphone.

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So $P = \frac{0.25}{0.83} = 0.3012$

The answer for question 4 is C.

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1 year ago