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AlladinOne [14]

2 years ago

15

The price of your service plan before taxes is 89.99. For your convenience, I will deduct 15% off your service plan before taxes

. The price you will pay after the discount has been applied and prior to taxes being added is?

1 answer:

Citrus2011 [14]2 years ago

5 0

First, you must find how much $ the discount takes off
89.99 * .15
=13.4985

Subtract that from 89.99

=76.4915

If you estimate it,
$ 76.49

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One nanometer equals about

Orlov [11]

Answer:

$1\ \text{nanometer}=4\times 10^8$

Step-by-step explanation:

Given : One nanometer equals about 0.00000004 inches.

To find : When writing this decimal as a single-digit integer multiplied by a power of ten, the single digit integer is and the power of ten ?

Solution :

$1\ \text{nanometer}=0.00000004$

$1\ \text{nanometer}=\frac{00000004}{100000000}$

$1\ \text{nanometer}=4\times 10^8$

Therefore, the decimal as a single-digit integer multiplied by a power of ten is $1\ \text{nanometer}=4\times 10^8$

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2 years ago

Solve the system of equations.<br> - 5x + 2y = 9

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Answer: -5x + 2y -9 = 0

Step-by-step explanation:

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2. Change the signs on both sides of the equation

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2 years ago

Verify the given linear approximation at a = 0. Then determine the values of x for which the linear approximation is accurate to

nikklg [1K]

Answer:

Part 1)

See Below.

Part 2)

$\displaystyle (-0.179, -0.178) \cup (-0.010, 0.012)$

Step-by-step explanation:

Part 1)

The linear approximation <em>L</em> for a function <em>f</em> at the point <em>x</em> = <em>a</em> is given by:

$\displaystyle L \approx f'(a)(x-a) + f(a)$

We want to verify that the expression:

$1-36x$

Is the linear approximation for the function:

$\displaystyle f(x) = \frac{1}{(1+9x)^4}$

At <em>x</em> = 0.

So, find f'(x). We can use the chain rule:

$\displaystyle f'(x) = -4(1+9x)^{-4-1}\cdot (9)$

Simplify. Hence:

$\displaystyle f'(x) = -\frac{36}{(1+9x)^{5}}$

Then the slope of the linear approximation at <em>x</em> = 0 will be:

$\displaystyle f'(1) = -\frac{36}{(1+9(0))^5} = -36$

And the value of the function at <em>x</em> = 0 is:

$\displaystyle f(0) = \frac{1}{(1+9(0))^4} = 1$

Thus, the linear approximation will be:

$\displaystyle L = (-36)(x-(0)) + 1 = 1 - 36x$

Hence verified.

Part B)

We want to determine the values of <em>x</em> for which the linear approximation <em>L</em> is accurate to within 0.1.

In other words:

$\displaystyle \left| f(x) - L(x) \right | \leq 0.1$

By definition:

$\displaystyle -0.1\leq f(x) - L(x) \leq 0.1$

Therefore:

$\displaystyle -0.1 \leq \left(\frac{1}{(1+9x)^4} \right) - (1-36x) \leq 0.1$

We can solve this by using a graphing calculator. Please refer to the graph shown below.

We can see that the inequality is true (i.e. the graph is between <em>y</em> = 0.1 and <em>y</em> = -0.1) for <em>x</em> values between -0.179 and -0.178 as well as -0.010 and 0.012.

In interval notation:

$\displaystyle (-0.179, -0.178) \cup (-0.010, 0.012)$

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2 years ago

the average of five numbers is 16. Suppose 10 is added to the five numbers what it the average of the six numbers

Lerok [7]

X/5 = 16
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