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2 years ago

11

Tickets to a movie cost $5 for adults and $3 for students. A group of friends purchased 18 tickets for $82.00. How many adults t

icket did they buy?

1 answer:

TEA [102]2 years ago

7 0

Answer:

They purchased 14 adult tickets and 4 kids tickets.

Step-by-step explanation:

14 x 5 = 70

3x4=12

and then add 70 plus 12 to get 82 dollars.

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Joanna, the line manager at Smedley Electronics, works 14 hours a week more than her line workers and gets paid $6.50 more per h

chubhunter [2.5K]

Given:
Joanna :
works 14 hrs a week more than her line workers.
gets paid 6.50 more per hour than her line workers.

Line workers: h = hours per week ; d = dollars per hour.

Line worker = Dollar per hour * number of hours.
Joanna = (Dollar per hour + 6.50)(number of hours + 14 hours)

Line worker:
$576 = d * 36 hours
$576/36 = d
$16 = d hourly rate of line worker.

Joanna:
$16 + 6.50 = $22.50 hourly rate
36hrs + 14hrs = 50 hours per week.

Weekly pay of Joanna: $22.50 * 50 = $1,125

5 0

1 year ago

Determine whether or not the vector field is conservative. if it is conservative, find a function f such that f = ∇f. (if the ve

sweet [91]

A conservative vector field $\mathbf f$ has curl $\nabla\times\mathbf f=\mathbf0$ . In this case,

$\nabla\times\mathbf f=12xy^2z(1-z)\,\mathbf j+4yz^2(2z-3x)\,\mathbf k\neq\mathbf 0$

so the vector field is not conservative.

3 0

2 years ago

A special 8-sided die is marked with the numbers 1 to 8. It is rolled 20 times with these outcomes:

horsena [70]

Answer:

One: B

Two: 60% and 10%

Step-by-step explanation:

Problem One

There are only two numbers in the sample of 40 that are under 26. Both are 25. If you find more, make the adjustment. There are 2 more that are exactly 26 but they are not counted because the directions say "less than 26."

So set up your proportion

x/2000 = 2/40 Multiply both sides by 2000

x = 2/40 * 2000

x = 4000/40

x = 100

A

I don't know where 5 comes from. But it is not correct.

B

B should be the correct answer.

C

Exactly 100 pieces should be defective. That is the theoretical result. C is incorrect.

D

D is not correct. The sample size would not be 40. It would have to be 2000 for D to be correct. So D is wrong.

E

We have enough data to get an answer. E is incorrect.

Problem 2

The think you must NOT do is count 1 as being prime. The prime numbers are 2 3 5 7 between 1 and 8. They break down as follows.

Prime Number of them
2 3
3 4
5 2
7 3

The total number of primes = 12

There are 20 numbers in the sample

The experimental probability of tossing a prime is 12/20 * 100% = 60%

The non primes are 2 3 5 7 which is 4 out of 8

4/8 * 100 = 50%

The experimental value is 10% more than the theoretical value.

Discussion

Note: the problem may be one. This all depends on what you have been told about 1. I am using the exact wording of prime here. 1 is not a prime. It is also not a composite. So it has to be counted as part of the non primes.

4 0

2 years ago

Read 2 more answers

Q3. a cyclist bikes x distance at 10 miles per hour and returns over the same path at 8 miles per hour. what is the cyclist's av

Sladkaya [172]

If he bikes for 10 miles per hour and 8 miles per hour for the same distance x miles, he went 10 miles per hour for x/10 hours, as Distance = Rate*Time and on the way back he would go for x/8 hours. So then he went 2x distance, in x/8 + x/10 hours. Since x/8 + x/10 = 10x/80 + 8x/80 = 18x/80 = 9x/40, he went 2x miles in 9x/40 hours. this can be converted into a rate with the above equation Distance = Rate*Time, so 2x=(9x/40) * Rate, thus we divide by 9x/40 on both sides to get 80x/9x = Rate, the x cancels out, and we get 80/9 Miles per hour.

4 0

2 years ago

Determine whether each of these sets is finite, countably infinite, or uncountable. For those that are countably in- finite, exh

mrs_skeptik [129]

Answer:

a) the negative integers set A is countably infinite.

one-to-one correspondence with the set of positive integers:

f: Z+ → A, f(n) = -n

b) the even integers set A is countably infinite.

one-to-one correspondence with the set of positive integers:

f: Z+ → A, f(n) = 2n

c) the integers less than 100 set A is countably infinite.

one-to-one correspondence with the set of positive integers:

f: Z+ → A, f(n) = 100 - n

d) the real numbers between 0 and 12 set A is uncountable.

e) the positive integers less than 1,000,000,000 set A is finite.

f) the integers that are multiples of 7 set A is countably infinite.

one-to-one correspondence with the set of positive integers:

f: Z+ → A, f(n) = 7n

Step-by-step explanation:

A set is finite when its elements can be listed and this list has an end.

A set is countably infinite when you can exhibit a one-to-one correspondence between the set of positive integers and that set.

A set is uncountable when it is not finite or countably infinite.

8 0

1 year ago