Answer:
One: B
Two: 60% and 10%
Step-by-step explanation:
Problem One
There are only two numbers in the sample of 40 that are under 26. Both are 25. If you find more, make the adjustment. There are 2 more that are exactly 26 but they are not counted because the directions say "less than 26."
So set up your proportion
x/2000 = 2/40 Multiply both sides by 2000
x = 2/40 * 2000
x = 4000/40
x = 100
A
I don't know where 5 comes from. But it is not correct.
B
B should be the correct answer.
C
Exactly 100 pieces should be defective. That is the theoretical result. C is incorrect.
D
D is not correct. The sample size would not be 40. It would have to be 2000 for D to be correct. So D is wrong.
E
We have enough data to get an answer. E is incorrect.
Problem 2
The think you must NOT do is count 1 as being prime. The prime numbers are 2 3 5 7 between 1 and 8. They break down as follows.
- Prime Number of them
- 2 3
- 3 4
- 5 2
- 7 3
The total number of primes = 12
There are 20 numbers in the sample
The experimental probability of tossing a prime is 12/20 * 100% = 60%
The non primes are 2 3 5 7 which is 4 out of 8
4/8 * 100 = 50%
The experimental value is 10% more than the theoretical value.
Discussion
Note: the problem may be one. This all depends on what you have been told about 1. I am using the exact wording of prime here. 1 is not a prime. It is also not a composite. So it has to be counted as part of the non primes.
