Answer:
D. The mathematical expectation of Option A is 1. The mathematical expectation of Option B is 1.5. Option B offers a greater likelihood of advancing to the finish line.
Step-by-step explanation:
The result of a product is odd only when the two numbers are odds.
There are 6*6 = 36 possible outcomes when two dice are rolled. Only 9 of them are a combination of two odd numbers: {1, 1} {1, 3} {1, 5} {3, 1} {3, 3} {3, 5} {5, 1} {5, 3} {5, 5}. Then 36 - 9 = 27 outcomes are even.
P(even) = 27/36 = 0.75
Option A) Mathematical expectation: 0.75*4 + 0.25*(-8) = 1
Option B) Mathematical expectation: 0.75*5 + 0.25*(-9) = 1.5
Answer:
I'm gonna have to say 54%.
Step-by-step explanation:
It says right in the question, "At a breakfast buffet, 54% of people choose coffee for their beverage"
Answer:
Boat traveled 553.24 feet towards the lighthouse.
Step-by-step explanation:
In the figure attached AB is the light house of height 200 feet.
Angle of depression of the boat from the top of a lighthouse = angle of elevation of the lighthouse from the boat = 14°52'
so 1' = 
degree
so angle of elevation at point C = 14 + 
So angle of elevation from C = (14 + 0.87) = 14.87°
Similarly, when boat arrives at point D angle of elevation = 45°10' = 45 + 
= 45.17°
Now we have to calculate the distance CD, traveled by the boat.
In ΔABC
tan14.87 = 
0.2655 =
BC = 
BC = 753.239 feet
Similarly in ΔABD
tan45.17 = 
1 =
BD = 200 feet
So distance CD = BC - BD
CD = 753.239 - 200
= 553.24 feet
Therefore, Boat traveled 553.24 feet towards the lighthouse.
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 17
For the alternative hypothesis,
µ < 17
This is a left tailed test.
Since the population standard deviation is not given, the distribution is a student's t.
Since n = 80,
Degrees of freedom, df = n - 1 = 80 - 1 = 79
t = (x - µ)/(s/√n)
Where
x = sample mean = 15.6
µ = population mean = 17
s = samples standard deviation = 4.5
t = (15.6 - 17)/(4.5/√80) = - 2.78
We would determine the p value using the t test calculator. It becomes
p = 0.0034
Since alpha, 0.05 > than the p value, 0.0043, then we would reject the null hypothesis.
The data supports the professor’s claim. The average number of hours per week spent studying for students at her college is less than 17 hours per week.
