A soccer ball is kicked into the air from the ground. If the ball reaches a maximum height of 25 ft and spends a total of 2.5 s
1 answer:
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Refer to the diagram shown below.
Let x = m∠ADB.
Because m∠BDC is 32° greater than m∠ADB, therefore
m∠BDC = x + 32°
Each angle of a rectangle is 90°, therefore
x + (x+32) = 90
2x + 32 = 90
2x = 58
x = 29°
x+32 = 61°
Answer:
m∠BDC = 61°
m∠ADB = 29°
Let x = m∠ADB.
Because m∠BDC is 32° greater than m∠ADB, therefore
m∠BDC = x + 32°
Each angle of a rectangle is 90°, therefore
x + (x+32) = 90
2x + 32 = 90
2x = 58
x = 29°
x+32 = 61°
Answer:
m∠BDC = 61°
m∠ADB = 29°
∠ROT=160°
∠SOT=100°
Now ∠SOR= ∠ROT - ∠SOT
∠ SOR = 160°-100°
∠ SOR =60°
It is given that measure of angle ROQ to equals the measure of angle QOS equals the measure of angle POT.
∠SOQ + ∠QOR = 60°
But ∠SOQ = ∠QOR
2∠SOQ=60°
∠SOQ=60°÷2
∠SOQ =30°
Also ∠POT=∠SOQ=∠ROQ=30°
