If SA=1/2lp+B, find p What is the formula for finding p?

1 answer:

8 0

You must get p by itself, so first subtract B from both sides: SA-B=1/2lp. Then multiply both sides by 2, which cancels out the 1/2: 2SA=lp. Then divide both sides by l: (2SA)/l=p.

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Write two expressions where the solution is 4

Angelina_Jolie [31]

There are many expressions that have solution 4. some are:
3+1 = 4
2+2 = 4
5-1 = 4
7-3 =4
8-4 = 4
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7 0

1 year ago

Jeanne wants to start collecting coins and orders a coin collection starter kit. The kit comes with three coins chosen at random

lesya692 [45]

Conditional probability is a measure of the probability of an event given that another event has occurred. If the event of interest is A and the event B is known or assumed to have occurred, "the conditional probability of A given B", or "the probability of A under the condition B", is usually written as P(A|B), or sometimes $P_B(A)$ .

The conditional probability of event A happening, given that event B has happened, written as P(A|B) is given by
$P(A|B)= \frac{P(A \cap B)}{P(B)}$

In the question, we were told that there are three randomly selected coins which can be a nickel, a dime or a quarter.

The probability of selecting one coin is $\frac{1}{3}$

Part A:
To find the probability that all three coins are quarters if the first two envelopes Jeanne opens each contain a quarter, let the event that all three coins are quarters be A and the event that the first two envelopes Jeanne opens each contain a quarter be B.

P(A) means that the first envelope contains a quarter AND the second envelope contains a quarter AND the third envelope contains a quarter.

Thus $P(A)= \frac{1}{3} \times \frac{1}{3} \times \frac{1}{3} = \frac{1}{27}$

P(B) means that the first envelope contains a quarter AND the second envelope contains a quarter

Thus $P(B)= \frac{1}{3} \times \frac{1}{3} = \frac{1}{9}$

Therefore, $P(A|B)=\left( \frac{ \frac{1}{27} }{ \frac{1}{9} } \right)= \frac{1}{3}$

Part B:
To find the probability that all three coins are different if the first envelope Jeanne opens contains a dime, let the event that all three coins are different be C and the event that the first envelope Jeanne opens contains a dime be D.

$P(C)= \frac{3}{3} \times \frac{2}{3} \times \frac{1}{3} = \frac{6}{27} = \frac{2}{9}$

 $P(D)= \frac{1}{3}$ 

Therefore, $P(C|D)=\left( \frac{ \frac{2}{9} }{ \frac{1}{3} } \right)= \frac{2}{3}$

3 0

2 years ago

The number of miles walked, y, varies directly with the number of hours walked, h. After 1.2 hours, Hal had walked 1.8 miles. Fi

Firdavs [7]

Answer:

30 divided by 1.8= 16.6

Step explanation:

7 0

1 year ago

figure PQRS is a parallelogram. What are the measures of angles P and S? ∠P = 20°; ∠S = 160° ∠P = 40°; ∠S = 140° ∠P = 140°; ∠S =

viktelen [127]

I believe it is C (p=140 s=40)

4 0

2 years ago

Read 2 more answers

On Monday, the closing value of a share of stock in Company ABC, was 74.01. On Tuesday, it closed at 73.67, and on Wednesday, it

Elenna [48]

Answer:

$957.71$

Step-by-step explanation:

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To Find: One shareholder owns $13$ shares of Company ABC's stock. What was the total value of their stock in this company at the close of Tuesday.