Answer:
b) 0.0608
Step-by-step explanation:
As it is mentioned that the next two days i.e 24 hours, the probability of the rain is uniformly distributed
Therefore the rain probability is

where,
T = Length of the time interval
Plus, as we know that rain is independent
So let us assume the rain between the 8: 40 AM and 2: 35 PM on single day is P1 and the time interval is 5 hours 55 minutes
i.e
= 5.91666 hours long.
So, P1 should be

= 0.2465
Now we assume the probability of rain on day 2 is P2
So it would be same i.e 0.2465
Since these events are independent
So, the total probability is

= 0.0608
Hence, the b option is correct
Evaluate 4-0.25g+0.5h4−0.25g+0.5h4, minus, 0, point, 25, g, plus, 0, point, 5, h when g=10g=10g, equals, 10 and h=5h=5h, equals,
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I believe the correct given equation is in the form of:
4 – 0.25 g + 0.5 h
Now we are to evaluate the equation with the given values:
g = 10 and h = 5
What this actually means is that to evaluate simply means
to calculate for the value of the equation by plugging in the values of the
variables. Therefore:
4 – 0.25 g + 0.5 h = 4 – 0.25 (10) + 0.5 (5)
4 – 0.25 g + 0.5 h = 4 – 2.5 + 2.5
4 – 0.25 g + 0.5 h = 4
Therefore the value of the equation is:
4
The probability of the pointer lands on red(R) both spin =
Step-by-step explanation:
Given,
The number of parts = 6
The pointer is spun twice.
To find the probability of the pointer lands on red(R) both spin.
Formula
Probability of an event = number of required outcomes ÷ the total number of outcomes.
P(A and B) = P(A)×P(B)
Now,
For one spin,
A = RED comes.
For second spin,
B = RED comes
So,
P(A) =
and P(B) =
Then,
P(A and B) =
×
=
Hence, the probability of the pointer lands on red(R) both spin =