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Marta_Voda [28]

2 years ago

7

Three students, Angie, Bradley, and Carnell, are being selected for three student council offices: president, vice president, an

d treasurer. In each arrangement below, the first initial of each person’s name represents that person’s position, with president listed first, vice president second, and treasurer third. Which shows the possible outcomes for the event? ABC ABC, BAC, CBA AAA, BBB, CCC ABC, ACB, BCA, BAC, CAB, CBA
PLEASE HELP!!!!!

2 answers:

Andrews [41]2 years ago

8 0

Answer:

A) ABC, ACB, BCA, BAC, CAB, CBA

Step-by-step explanation:

Naddik [55]2 years ago

6 0

Answer: D

Step-by-step explanation:

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There are approximately 0.4536 kilograms in a pound. To the nearest whole pound, how many pounds does a steer that weighs 200 kg

Sergio039 [100]

Answer:

i need help with this one too plz help

Step-by-step explanation:

5 0

1 year ago

Plz answer quickly!!!!!!!

ValentinkaMS [17]

Answer:

<em>(A). x ≥ </em> $\frac{16}{5}$ <em> and x ≤ - </em> $\frac{3}{4}$ <em> </em>

Step-by-step explanation:

5x - 4 ≥ 12 ⇔ 5x ≥ 16 ⇒ <em>x ≥ </em> $\frac{16}{5}$ <em> </em>

<em>and </em>

12x + 5 ≤ - 4 ⇔ 12x ≤ - 9 ⇔ 4x ≤ - 3 ⇒ <em>x ≤ - </em> $\frac{3}{4}$

6 0

1 year ago

Keenan currently does a total of 888 pushups each day. He plans to increase the number of pushups he does each day by 222 pushup

marishachu [46]

Answer:

8 + 2x = 30

Step-by-step explanation:

Given,

The initial number of push-ups he does in each day = 8,

And, the number of push-ups, he increases per day = 2,

Let x be the number of days after he will reach his target of 30 push-ups,

Since, the number of push-ups she will increase in x days = 2x,

Thus, the number of push-ups she will do after x days = 8 + 2x,

⇒ 8 + 2x = 30, which is the required equation.

4 0

1 year ago

Question:twice as much as the sum of eighteen and eleven<br><br> in numbers and don't solve

Dmitrij [34]

2(18+11)
i think this is the expression you are looking for

3 0

1 year ago

Read 2 more answers

I tell you these facts about a mystery number, $c$: $\bullet$ $1.5 < c < 2$ $\bullet$ $c$ can be written as a fraction wit

makkiz [27]

Answer:

Possible answer: $\displaystyle c = \frac{16}{10} = \frac{8}{5} = 1.6$ .

Step-by-step explanation:

Rewrite the bounds of $c$ as fractions:

The simplest fraction for $1.5$ is $\displaystyle \frac{3}{2}$ . Write the upper bound $2$ as a fraction with the same denominator:

$\displaystyle 2 = 2 \times 1 = 2 \times \frac{2}{2} = \frac{4}{2}$ .

Hence the range for $c$ would be:

$\displaystyle \frac{3}{2} < c < \frac{4}{2}$ .

If the denominator of $c$ is also $2$ , then the range for its numerator (call it $p$ ) would be $3 < p < 4$ . Apparently, no whole number could fit into this interval. The reason is that the interval is open, and the difference between the bounds is less than $2$ .

To solve this problem, consider scaling up the denominator. To make sure that the numerator of the bounds are still whole numbers, multiply both the numerator and the denominator by a whole number (for example, 2.)

$\displaystyle \frac{3}{2} = \frac{2 \times 3}{2 \times 2} = \frac{6}{4}$ .

$\displaystyle \frac{4}{2} = \frac{2\times 4}{2 \times 2} = \frac{8}{4}$ .

At this point, the difference between the numerators is now $2$ . That allows a number ( $7$ in this case) to fit between the bounds. However, $\displaystyle \frac{1}{c} = \frac{4}{7}$ can't be written as finite decimals.

Try multiplying the numerator and the denominator by a different number.

$\displaystyle \frac{3}{2} = \frac{3 \times 3}{3 \times 2} = \frac{9}{6}$ .

$\displaystyle \frac{4}{2} = \frac{3\times 4}{3 \times 2} = \frac{12}{6}$ .

$\displaystyle \frac{3}{2} = \frac{4 \times 3}{4 \times 2} = \frac{12}{8}$ .

$\displaystyle \frac{4}{2} = \frac{4\times 4}{4 \times 2} = \frac{16}{8}$ .

$\displaystyle \frac{3}{2} = \frac{5 \times 3}{5 \times 2} = \frac{15}{10}$ .

$\displaystyle \frac{4}{2} = \frac{5\times 4}{5 \times 2} = \frac{20}{10}$ .

It is important to note that some expressions for $c$ can be simplified. For example, $\displaystyle \frac{16}{10} = \frac{2 \times 8}{2 \times 5} = \frac{8}{5}$ because of the common factor $2$ .

Apparently $\displaystyle c = \frac{16}{10} = \frac{8}{5}$ works. $c = 1.6$ while $\displaystyle \frac{1}{c} = \frac{5}{8} = 0.625$ .

8 0

2 years ago

Read 2 more answers