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lara31 [8.8K]
2 years ago
8

A group of 14 friends collects 0.7 pound of blueberries and decides to make blueberry muffins. They put 0.05 pound of berries in

each muffin. How many muffins can they make if they use all the blueberries they collected?
Mathematics
2 answers:
saul85 [17]2 years ago
8 0
They can make 14 muffins
xz_007 [3.2K]2 years ago
6 0

They can make 14 muffins using all the blueberries they have collected.

<h3 /><h3>Further Explanation</h3>

<u>Given:</u>

  • 14 friends collect 0.7 pounds of blueberries
  • Each muffin has 0.05 pounds of berries

<u>Question:</u>

How many muffins can they make if they use all the blueberries they collected?

The number of muffin they can make using the 0.7 pounds of blueberries

= Total blueberries they have collected : blueberries in each muffin

\boxed {= \frac{0.7}{0.05} }

To solve a decimal divided by-a decimal, we need to change them into a whole number by multiply the denominator and numerator with 1, 100 or 100 to shift the decimal place.

First, we can write the equation in fraction

\boxed {= \frac{0.7}{0.05} }\\\boxed {= \frac{0.7 \times100}{0.05 \times100} =\frac{70}{5} = 14}\\

In the above equation we multiply both the denominator and numerator with 100 to make it a whole number, we can't multiply the denominator with 100 and the numerator with 10. It should be the same number.

So with the blueberries they have collected, they can make 14 muffins.

<h3 /><h3>Learn more</h3>

Divided a decimal number brainly.com/question/3365642

Total spend brainly.com/question/12203917

Decimal multiplication brainly.com/question/2124592

Decimal multiplication brainly.com/question/1254534

Keywords: fraction, dividing a decimal-by-a decimal, dividing decimal, division problem

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Suppose a continuous probability distribution has an average of μ=35 and a standard deviation of σ=16. Draw 100 times at random
yulyashka [42]

Answer:

To use a Normal distribution to approximate the chance the sum total will be between 3000 and 4000 (inclusive), we use the area from a lower bound of 3000 to an upper bound of 4000 under a Normal curve with its center (average) at 3500 and a spread (standard deviation) of 160 . The estimated probability is 99.82%.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For sums, we have that the mean is \mu*n and the standard deviation is s = \sigma \sqrt{n}

In this problem, we have that:

\mu = 100*35 = 3500, \sigma = \sqrt{100}*16 = 160

This probability is the pvalue of Z when X = 4000 subtracted by the pvalue of Z when X = 3000.

X = 4000

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{4000 - 3500}{160}

Z = 3.13

Z = 3.13 has a pvalue of 0.9991

X = 3000

Z = \frac{X - \mu}{s}

Z = \frac{3000 - 3500}{160}

Z = -3.13

Z = -3.13 has a pvalue of 0.0009

0.9991 - 0.0009 = 0.9982

So the correct answer is:

To use a Normal distribution to approximate the chance the sum total will be between 3000 and 4000 (inclusive), we use the area from a lower bound of 3000 to an upper bound of 4000 under a Normal curve with its center (average) at 3500 and a spread (standard deviation) of 160 . The estimated probability is 99.82%.

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2 years ago
A woman who is 64 inches tall has a shoulder width of 16 inches. How tall is a woman who has a shoulder width of 18.5 inches?
mel-nik [20]
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Alex777 [14]
Do the opposite of what you did in reverse order.

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Answer:

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Step-by-step explanation:

<u><em>Explanation:-</em></u>

Given that the expression ( x y -6)²

Apply formula (a-b)² = a² -2ab + b²

( x y -6)² = (xy)² - 2 × xy× 6 + (6)²

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( x y -6)²  =  x² y² - 12 xy + 36            

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Substitute in the values:

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Multiply both sides by sin(41.5)

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The correct answer would be C. 36.64

<h3><u>✽</u></h3>

➶ Hope This Helps You!

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➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

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1 year ago
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