The complete problem wants to know the more cost-effective choice is the printing company replaces its press machine every four years.
With this in mind, if they choose Company A, the total amount that needs to be paid to cover 12(4) = 48 months will be
Company A = 9 500 + 48(750) = $13 100
As for Company B, the highest probability of not having any repairs over the four years is 0.32 while there's 0.14 chance that number of repairs will be 3 over the time the contract is applied.
This means that the possible amounts to be paid to Company B are
Company B = 10 500 + 0(150) = $10 500
Company B = 10 500 + 1(150) = $10 650
Company B = 10 500 + 2(150) = $10 800
Company B = 10 500 + 3(150) = $10 950
This shows that choosing the machine from Company B would be better.
Hence, the answer is Company B<span>.</span>
Answer:
The total number of bugs in the collection is 36
Step-by-step explanation:
Let
x -----> the number of bugs that you find out
y ----> the number of bugs that the classmate find out
we know that
-----> equation A
----> equation B
Solve the system by graphing
Remember that the solution is the intersection point both graphs
The solution is the point (20,16)
The total number of bugs in the collection is

Find the z-scores for the two scores in the given interval.

For the score x =391,

.
For the score x = 486,

Now you want the area (proportion of data) under the normal distribution from z = -1 to z = 0. The Empirical Rule says that 68% of the data falls between z = -1 to z = 1. But the curve is symmetrical around the vertical axis at z = 0, so the answer you want is HALF of 68%.
Answer:
782 in
Step-by-step explanation:
To find the length of fence, we have to find the perimeter first.
Given
Length = l = 25 feet 8 in
Width = w = 8 feet 8 in
Opening = o =3 feet 6 in
So,
we have to convert the lengths into same unit first
So,
l = (25*12)+8 = 308 in
w = ( 8*12) +8 = 104 in
O = (12*3) + 6 = 42 in
Perimeter = 2(l+w)
= 2(308+104)
=2(412)
=824
As the opening does not need fencing
Total fence = P - o
= 824 - 42
=782 in
or
65 feet 2 in ..