The perimeter is the sum of the enclosing side.
From the figure, the perimeter is
P = 11 + (x-2) + (11-3) + [(x-2) - (x-11)] + (x-11)
= 11 + x - 2 + 8 + 9 + x - 11
= 2x + 15
Answer: 2x + 15
Answer:
23rd term
Step-by-step explanation:
Plz mark as Brainliest!
Answer:
The value of k is 3.
Step-by-step explanation:
The function f(x) passes through the points (0,4) and (-6,-2)
So the equation of the function is
⇒ y = x + 4 ....... (1)
Again the function g(x) passes through the points (0,4) and (-2,-2).
Therefore, the equation of g(x) will be
⇒ y = 3x + 4
Therefore, g(x) = 3x + 4 = f(3x) {from equation (1).
So, the value of k is 3. (Answer)
(a) 0.059582148 probability of exactly 3 defective out of 20
(b) 0.98598125 probability that at least 5 need to be tested to find 2 defective.
(a) For exactly 3 defective computers, we need to find the calculate the probability of 3 defective computers with 17 good computers, and then multiply by the number of ways we could arrange those computers. So
0.05^3 * (1 - 0.05)^(20-3) * 20! / (3!(20-3)!)
= 0.05^3 * 0.95^17 * 20! / (3!17!)
= 0.05^3 * 0.95^17 * 20*19*18*17! / (3!17!)
= 0.05^3 * 0.95^17 * 20*19*18 / (1*2*3)
= 0.05^3 * 0.95^17 * 20*19*(2*3*3) / (2*3)
= 0.05^3 * 0.95^17 * 20*19*3
= 0.000125* 0.418120335 * 1140
= 0.059582148
(b) For this problem, let's recast the problem into "What's the probability of having only 0 or 1 defective computers out of 4?" After all, if at most 1 defective computers have been found, then a fifth computer would need to be tested in order to attempt to find another defective computer. So the probability of getting 0 defective computers out of 4 is (1-0.05)^4 = 0.95^4 = 0.81450625.
The probability of getting exactly 1 defective computer out of 4 is 0.05*(1-0.05)^3*4!/(1!(4-1)!)
= 0.05*0.95^3*24/(1!3!)
= 0.05*0.857375*24/6
= 0.171475
So the probability of getting only 0 or 1 defective computers out of the 1st 4 is 0.81450625 + 0.171475 = 0.98598125 which is also the probability that at least 5 computers need to be tested.
So, basically ..you just multiply
9*9*9*9
6561