I hope I can show the image, but I hope this may help you, the answer is:
The center of the inscribed circle of ΔABC is <u>point S</u> , and the center of the circumscribed circle of ΔABC is <u>point P.</u>
We let x and y be the measures of the sides of the
rectangular garden. The perimeter subtracted with the other side should be
equal to 92.
<span> 2x + y = 92</span>
The value of y in terms of x is equal to,
<span> y =
92 – 2x</span>
The area is the product of the two sides,
<span>
A
= xy</span>
Substituting,
<span> A
= x (92 – 2x) = 92x – 2x2</span>
Solving for the derivative and equating to zero,
<span> 0
= 92 – 4x ; x = 23</span>
Therefore, the area of the garden is,
<span> A
= 23(92 – 2(23)) = 1058 yard<span>2</span></span>
Thanks for posting your question here. The answer to the above problem is x = <span>48.125. Below is the solution:
</span>
x+x/7+1/11(x+x/7)=60
x = x/1 = x • 7/7
x <span>• 7 + x/ 7 = 8x/7 - 60 = 0
</span>x + x/7 + 1/11 <span>• 8x/7 - 60 = 0
</span>8x <span>• 11 + 8x/ 77 = 96x/ 77
</span>96x - 4620 = 12 <span>• (8x-385)
</span>8x - 385 = 0
x = 48.125
It could only be scalene or isosceles ... an equilateral triangle has all 60 degree angles
Isosceles- 90-45-45 degrees
Scalene- 90-35-55 degrees