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juin [17]
2 years ago
13

The percentage of people given an antirheumatoid who suffer severe, moderate, or minor side effects are 11, 20 and 69%, respecti

vely. Assume that people react independently and that 20 people are given the medicine. Determine the following. Round your answers to four decimal places (e.g. 98.7654). (a) The probability 2, 4, and 14 people will suffer severe, moderate, or minor side effects, respectively.
Mathematics
1 answer:
Snowcat [4.5K]2 years ago
6 0

Answer:2.9235

Step-by-step explanation:

Since 20 people are administered the medicine and;

11% of the 20 people suffer severe i.e 11% of 20 = 2.2 people

20% of them suffer moderate i.e

20% of 20 = 4 people and;

69% of the 20 people suffer minor side i.e

69% of 20 = 13.8 people

Therefore the probability 2, 4, and 14 people will suffer severe, moderate, or minor side effects, respectively will be;

2/2.2 + 4/4 + 14/13.8 (i.e possible outcome/total outcome)

This will give us 2.9235

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Solve each of the following initial value problems and plot the solutions for several values of y0. Then describe in a few words
Taya2010 [7]

Answer:

Step-by-step explanation:

Answer:

a) y-8 = (y₀-8)  , b) 2y -5 = (2y₀-5)

Explanation:

To solve these equations the method of direct integration is the easiest.

a) the given equation is

          dy / dt = and -8

         dy / y-8 = dt

We change variables

          y-8 = u

         dy = du

We replace and integrate

           ∫ du / u = ∫ dt

           Ln (y-8) = t

We evaluate at the lower limits t = 0 for y = y₀

          ln (y-8) - ln (y₀-8) = t-0

Let's simplify the equation

           ln (y-8 / y₀-8) = t

           y-8 / y₀-8 =

            y-8 = (y₀-8)

b) the equation is

            dy / dt = 2y -5

            u = 2y -5

            du = 2 dy

            du / 2u = dt

We integrate

             ½ Ln (2y-5) = t

We evaluate at the limits

            ½ [ln (2y-5) - ln (2y₀-5)] = t

            Ln (2y-5 / 2y₀-5) = 2t

            2y -5 = (2y₀-5)

c) the equation is very similar to the previous one

             u = 2y -10

             du = 2 dy

             ∫ du / 2u = dt

             ln (2y-10) = 2t

We evaluate

             ln (2y-10) –ln (2y₀-10) = 2t

               2y-10 = (2y₀-10)

4 0
2 years ago
The diagram shows some land in the shape of a quadrilateral ABCD. AB = 6 km, AD = 5 km and CD = 12 km Angle BAC = 30 The land is
Goshia [24]

Answer:

£495 million

Step-by-step explanation:

To find out the total cost of the land, we need to first calculate the area of the land.

Step 1: Find area of right angled triangle ADC

AD = 5 km,

DC = 12 km

Area of the right triangle = ½*a*b

a = 5km

b = 12km

Area = ½*5*12

= 5*6

Area of ADC = 30 km²

Step 2: Find the area of triangle ABC

First, let's find the length of AC using Pythagorean theorem

AC² = AD² + DC²

AC² = 5² + 12² = 25 + 144

AC = √169

AC = 13km

Area of ∆ABC = ½*AB*AC*sin(30°)

= ½*6*13*0.5

= 3*13*0.5

Area of ∆ABC = 19.5 km²

Total area of the land = area of ∆ADC + ∆ABC = 30 + 19.5 = 49.5 km²

Step 3: calculate how much the land costs

If the land costs £10 million per km²,

Cost of 49.5 km² = 49.5 × 10 = £495 million

4 0
2 years ago
If George is 33 1/3% richer than Pete, than Pete is what percent poorer than George?
OleMash [197]

Answer:

25%

Step-by-step explanation:

George is 33\frac{1}{3}% (\frac{100}{3}%) richer than Pete. Let Pete's percentage of wealth be 100%.

Thus George percentage of wealth = 100% + \frac{100}{3}%

                                                           = \frac{400}{3}%

                                                           = 133\frac{1}{3}%

Pete's percent poorer than George can be determined by;

                                                           = (\frac{100}{3}) ÷ (\frac{400}{3} ) × 100

                                                           = (\frac{100}{3}) × \frac{3}{400} ×100

                                                           = 0.25 × 100

                                                           = 25%

Pete is 25% poorer than George.

3 0
2 years ago
the loudness in decibels of sound is defined as 10 log I/I0, where I is the intensity of the sound in watts per square meter (W/
Oxana [17]
As the problem states, to solve this, we are going to use the equation L= log \frac{I}{I_{0} }
where 
L is the loudness in dB
I is the intensity of a sound 
I_{0}  <span>is the minimum intensity detectable by the human ear
</span>
We know for our problem that I=1.65*10^{-2}; we also now that the minimum intensity detectable by the human ear is 10^{-12)W/m^{2}, so I_{0}=10^{-12}. Lets replace those values in our equation to find L:
L=log \frac{1.65*10^{-2} }{10^{-12}}
L=10.22dB

Qe can conclude that since the explosion is under 100dB, it does not violates the regulation of the town. We used tow physical values to calculate the answer: the intensity of the sound of the explosion, I=1.65*10^{-2}W/m^2, and the minimum intensity detectable by the human ear I_{0}=10^{-12}W/m^{2}.
3 0
2 years ago
Write an expression using the distributive property to find the product of 7×63
alekssr [168]
(7x6) + (7x3) = c. this is the answer
5 0
2 years ago
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