A(n) = –3 • 2⁽ⁿ⁻¹⁾
for n = 1 , A₁ = -3.(2)⁰ = -3
for n = 2 , A₂ = -3.(2)¹ = -6
for n = 3 , A₃ = -3.(2)² = -12
for n = 4 , A₄ = -3.(2)³ = -24
...........................................
for n = 8 , A₈ = -3.(2)⁷ = -384
Answer:
same amount of money
Step-by-step explanation:
Answer:
The answer is 3√5 mi.
The formula is: d = √(3h/2)
Wyatt:
h = 120 ft
d = √(3 * 120/2) = √180 = √(36 * 5) = √36 * √5 = 6√5 mi
Shawn:
h = 270 ft
d = √(3 * 270/2) = √405 = √(81 * 5) = √81 * √5 = 9√5 mi
How much farther can Shawn see to the horizon?
Shawn - Wyatt = 9√5 - 6√5 = 3√5 mi
∑ from 1 to infinity of 12(3/5)^(i - 1)
Since the common ratio is less than 1, the series is convegent. [i.e. 3/5 < 1]
Sum to infinity of a geometric series is given by a/(1 - r); where a is the first term, and r is the common ratio.
Sum = 12/(1 - 3/5) = 12/(2/5) = 30.
Answer:
99% Confidence interval: (0.185,0.375)
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 150
Number of cars that have faulty catalytic converters, x = 42
99% Confidence interval:
Putting the values, we get:
The 99% confidence interval for the true proportion of new cars with faulty catalytic converters is (0.185,0.375)
