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Setler [38]
2 years ago
8

1. tentukan hasil dari 243⅔?

Mathematics
1 answer:
Vesnalui [34]2 years ago
7 0

Penjelasan langkah demi langkah:

1)

= 243^{\frac{2}{3} }\\= (\sqrt[3]{243})^2\\= 7^2\\= 49

2) √32 +3√18-2√50

= √16*2 +3√9*2-2√25*2

= 4√2 + 3(3√2)-2(5√2)

= 4√2 + 9√2-10√2

= 13√2-10√2

= 3√2

3) 1000 ⅔×64⅙

 = (\sqrt[3]{1000}) ^2 \times (2^6)^{1/6}  \\= 10^2 \times 2\\= 100 \times 2\\= 200

4) 3/4+√2

3/4+\sqrt{2} \\= \frac{3+4\sqrt{2} }{4 }

5) 2√3×√18

= 2√3×√9*2

= 2√3×3√2

= (2*3)(√3*√2)

= 6√6

6) 12/3+√3

= 4+√3

7) √1000—2√40

= 10 -2 (√4*10)

= 10-2(2√10)

= 10 - 4√10

8) 2- ¹+3-¹

= \frac{1}{2} + \frac{1}{3}\\ = \frac{3+2}{6}\\ = \frac{5}{6}

9)

\frac{5}{\sqrt{5} }\\ merasionalisasikan\\= \frac{5}{\sqrt{5} }\times \frac{\sqrt{5} }{\sqrt{5} }\\= \frac{5\sqrt{5} }{\sqrt{25} }\\= \frac{5\sqrt{5} }{5}\\ = \frac{\sqrt{5} }{1}

Jika pernyataannya opsional, penyebutnya adalah 1

10) 2√3×√18

= 2√3×√9*2

= 2√3×3√2

= (2*3)(√3*√2)

= 6√6

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alexdok [17]

Answer:

The upper bound is 97.5 cm

Step-by-step explanation:

The upper bound is given as the value that is larger than or equal to all values in a data set, for example, in the data set, {3, 6, 16, 23, 25}, an upper bound  is 25, however, where the accuracy of the data is given, the upper bound can be found by the following relation

Where the number is given to the nearest 100, add and subtract  half of hundred to obtain the upper bound and lower bound respectively

For the question, given that the size of the television is given as 95 cm, correct to the nearest 5 cm, we add add half of 5 cm to get the upper bound as follows;

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Lines e and f are parallel. The m9 = 80° and m5 = 55°. Which angle measures are correct? Check all that apply. m2 = 125° m3 = 55
Scorpion4ik [409]

I’ve answered this question before, so please see the attached image.

The solution would be like this for this specific problem:

 

1, 4, 5, 8 = 55<span>
2, 3 , 6, 7 = 125
9, 12, 13, 16 = 80
10, 11, 14 ,15 = 100</span>

<span>So, the angle measures that are correct are:

</span>

m12 = 100

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Answer:

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Step-by-step explanation:

For the sake of convenience, let us label ships A and B

As shown in the figure, the distances to the ships from right triangles.

The distance to the ship A is d_1 and it is given by

tan (61^o)= \dfrac{50}{d_1}

d_1=\dfrac{50}{tan (61^o)}

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And the distance to the ship B is d_2 and is given by

tan (28^o)= \dfrac{50}{d_2}

d_2=\dfrac{50}{tan (28^o)}

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Therefore, the distance d between the ships A and B is

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In other words, the ships are 66 meters apart.

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