Since length of diagonal ( 
) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without touching the edge of the circle.
<u>Step-by-step explanation:</u>
Here we have , A circle has diameter of 11 cm A square has side length of 7 cm . Use Pythagoras’ Theorem to show that the square will fit inside the circle without touching the edge of the circle . Let's find out:
We know the concept that for any square to fit inside the circle without touching the edge of circle , diagonal of square must be less than diameter of circle . Let's find out length of diagonal by using Pythagoras Theorem :
For a square , 
⇒ 
⇒ 
⇒ 
⇒
Since length of diagonal ( ) is less than diameter of circle ( 11 cm ) , Therefore , the square will fit inside the circle without ruching the edge of the circle.
We will take the volume of each box separately to find the difference between them.
We have then that the volume of the boxes is:
V = (L) * (W) * (h)
Where,
L: long
W: width
h: height
The smaller box:
V1 = (12) * (2) * (7 3/4)
V1 = 186 in ^ 3
the lager box:
V2 = (12) * (2) * ((7 3/4) * (100/80))
V2 = 232.5 in ^ 3
The difference is:
V2-V1 = 232.5 in ^ 3 - 186 in ^ 3 = 46.5 in ^ 3
Answer:
The difference in the volumes of the two boxes is:
46.5 in ^ 3
If the glasses were origanum 40, and were on sale for 26,we minus them from eachother to find out how much money was saved. So 40-26= 14, if $14 was saved we put 14 over the original price and times it buy 100 14/40x100= 35%
So 35% was saved. 100-35= 65. Therefore 65% of the original price was paid and 35% was saved.
