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2 years ago

What is the approximate area of the circle shown below?

Mathematics

2 answers:

oksano4ka [1.4K]2 years ago

7 0

Answer:

it should be 201.062

Step-by-step explanation:

area of a circle is pi times the radius to the power of 2.

Karolina [17]2 years ago

4 0

Answer:

A is approximately 201 cm^2

Step-by-step explanation:

The diameter of the circle is 16 so the radius is 1/2 of the diameter

1/2 * 16 = 8

The area of the circle is

A = pi r^2

A = 3.14 * 8^2

A =200.96 cm^2

A is approximately 201 cm^2

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Tim has developed a money saving strategy that uses the formula S=450+100r.

Sergeu [11.5K]

A) For 100R, that might mean every week, he is putting 100 dollars away for an interpretation.
B) The Slope represents the time it takes to make 100 dollars, and S represents the total amount of money Tim has.
C) If Tim got to 1250 dollars, it would be 8 for R. So 8 would be the domain and 1250 for the range.

5 0

2 years ago

Read 2 more answers

11. S(-4,-6) and T(-7, -3); Find R. What is the missing endpoint if S is the midpoint of RT

Nezavi [6.7K]

answer is (-7,-9)

step by step:-

S is the midpoint of RT so ,

s= $\frac{R+T}{2 }$

$-4=\frac{x-7}{2}$ , $-6=\frac{y-3}{2}$

$-14=x-7$ , $-12=y-3$

$x=-7$ , $y=-9$

R= (-7,-9)

5 0

2 years ago

in a random sample of 200 people, 154 said that they watched educational television. fine the 90% confidence interval of the tru

melisa1 [442]

Answer:

[0.7210,0.8189] = [72.10%, 81.89%]

Step-by-step explanation:

The sample size is

n = 200

the proportion is

p = 154/200 = 0.77

Since both np ≥ 10 and n(1-p) ≥ 10

We can approximate this discrete binomial distribution with the continuous Normal distribution. As the sample size is large enough, not applying the continuity correction factor makes no significant difference.

The approximation would be to a Normal curve with this parameters:

Mean

p = 0.77

Standard deviation

$\bf s=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.77*0.23}{200}}=0.0298$

The 90% confidence interval for the proportion would be then

$\bf [0.77-z^*0.0298, 0.77+z^*0.0298]$

where $\bf z^*$ is the 10% critical value for the Normal N(0,1) distribution , this is a value such that the area under the N(0,1) curve outside the interval $\bf [-z^*,z^*]$ is 10%=0.1

We can either use a table, a calculator or a spreadsheet to get this value.

In Excel or OpenOffice Calc we use the function

NORMSINV(0.95) and we get a value of 1.645

The 90% confidence interval for the proportion is then

$\bf [0.77-1.645^*0.0298, 0.77+1.645^*0.0298]=[0.7210,0.8189]$

This means there is a 90% probability that the proportion of people who watch educational television is between 72.10% and 81.89%

If the television company wanted to publicize the proportion of viewers, do you think it should use the 90% confidence interval?

Yes, I do.

5 0

2 years ago

What integer is equivalent to 25 3/2

antiseptic1488 [7]

Answer
26 1/2 is not equivalent to and integer but it can be approximated to 27 which is an integer.

Explanation
An integer is a whole number. It is a number that is not a fraction.
253/2=25+3/2=25+1 1/2=26 1/2
26 1/2 is not equivalent to and integer but it can be approximated to 27 which is an integer.

3 0

1 year ago

Read 2 more answers

Find where the slope of the curve is defined: x^2y-xy^2=4

Natali [406]

You do the implcit differentation, then solve for y' and check where this is defined.
In your case: Differentiate implicitly: 2xy + x²y' - y² - x*2yy' = 0
Solve for y': y'(x²-2xy) +2xy - y² = 0
y' = (2xy-y²) / (x²-2xy)
Check where defined: y' is not defined if the denominator becomes zero, i.e.
x² - 2xy = 0 x(x - 2y) = 0
This has formal solutions x=0 and y=x/2. Now we check whether these values are possible for the initially given definition of y:
0^2*y - 0*y^2 =? 4 0 =? 4
This is impossible, hence the function is not defined for 0, and we can disregard this.
x^2*(x/2) - x(x/2)^2 =? 4 x^3/2 - x^3/4 = 4 x^3/4 = 4 x^3=16 x^3 = 16 x = cubicroot(16)
This is a possible value for y, so we have a point where y is defined, but not y'.
The solution to all of it is hence D - { cubicroot(16) }, where D is the domain of y (which nobody has asked for in this example :-).
(Actually, the check whether 0 is in D is superfluous: If you write as solution D - { 0, cubicroot(16) }, this is also correct - only it so happens that 0 is not in D, so the set difference cannot take it out of there ...).
If someone asks for that D, you have to solve the definition for y and find that domain - I don't know of any [general] way to find the domain without solving for the explicit function).

3 0

2 years ago