Answer:
Hello there!
The answer to your question is :
<em>C: Finn needs 6 cups of sugar for 4 cakes.</em>
<em>D: Finn needs 1 1/2 cups of sugar for 1 cak</em>e.
Step-by-step explanation:
The graph clearly shows ( sides cups of sugar) (bottom number of cakes)
For sugar you need 6 cups to make 4 cakes
For sugar on the second question you need 1 1/2 cups of sugar to make 1 cake
Multiply 1 1/2 times 6 then divide and your answer is 4. That's 4 cakes out of 6 cups of sugar out of the original cups of sugar ( 1 1/2)
This is the confirmed answer I took the quiz and got 100%
Hopes this helps you!
~Darlington
A) set x as the number of cameras
18x=9x+1800
9x=1800
x=200
b) i'm assuming it's increasing production from my answer in a, so the profit would be 18(250)-(9*250+1800)=4500-4050=450
The domain is
{x | x >=0}
Or simply [0, infinity)
Since Haley can not use any negative minutes.
The range is
{y | y >=20}
Or simply [20, infinity)
This is because if Haley doesn't use any minutes, the price will stay at $20.
Let me know if you have any questions.
Answer:
The probability of a selection of 50 pages will contain no errors is 0.368
The probability that the selection of the random pages will contain at least two errors is 0.2644
Step-by-step explanation:
From the information given:
Let q represent the no of typographical errors.
Suppose that there are exactly 10 such errors randomly located on a textbook of 500 pages. Let
be the random variable that follows a Poisson distribution, then mean 
and the mean that the random selection of 50 pages will contain no error is 
∴

Pr(q =0) = 0.368
The probability of a selection of 50 pages will contain no errors is 0.368
The probability that 50 randomly page contains at least 2 errors is computed as follows:
P(X ≥ 2) = 1 - P( X < 2)
P(X ≥ 2) = 1 - [ P(X = 0) + P (X =1 )] since it is less than 2
![P(X \geq 2) = 1 - [ \dfrac{e^{-1} 1^0}{0!} +\dfrac{e^{-1} 1^1}{1!} ]](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%202%29%20%3D%201%20-%20%5B%20%5Cdfrac%7Be%5E%7B-1%7D%201%5E0%7D%7B0%21%7D%20%2B%5Cdfrac%7Be%5E%7B-1%7D%201%5E1%7D%7B1%21%7D%20%5D)
![P(X \geq 2) = 1 - [0.3678 +0.3678]](https://tex.z-dn.net/?f=P%28X%20%5Cgeq%202%29%20%3D%201%20-%20%5B0.3678%20%2B0.3678%5D)

P(X ≥ 2) = 0.2644
The probability that the selection of the random pages will contain at least two errors is 0.2644