Which inequality shows that Jerome wants to have read at least 85 pages by the end of Friday
2 answers:
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Answer:
1) 15cm
2) left projection/h = h/right projection
Step-by-step explanation:
Question:
1) The projections of the legs of a right triangle on the hypotenuse have lengths of 9 cm and 25 cm. Find the length of the height at the top of the right angle.
2) In a right triangle the length of the hypotenuse is 34 cm, and the lengths of the projections of the legs on the hypotenuse are directly proportional to the numbers 0, (6) and 0.75. Calculate the length of the height corresponding to the hypotenuse.
Solution
1) The length of the height of a right angle triangle is also called the altitude.
Since there are no diagrams in the question, I sent a diagram of the right angle as an attachment to the solution.
The projections of the legs are 25cm and 9cm.
Hence, the longer projection length AD = 25cm and the shorter projection length DB = 9cm
In a right triangle, the altitude (height) drawn from the right angle to the hypotenuse divides the hypotenuse into two segments. The length of the altitude is the
geometric mean of these two segments (the two projections) and it's given by:
left projection/h = h/right projection
AD/h = h/DB
25/h = h/9
Cross multiply
h^2 = 25×9
h =√225 = 15cm
The length of the height at the top of the triangle = 15cm
2) Length of hypotenuse = 34
From the question, the lengths of the projections of the legs on the hypotenuse are directly proportional to the numbers 0, (6) and 0.75.
There is an error with the figures because the sum of the length of the projection of the legs should be equal to the hypotenuse but it isn't in this case.
To calculate the length of the height corresponding to the hypotenuse, we would use the same formula above.
left projection/h = h/right projection
To find each leg using question 1 above, each leg of the triangle is the mean proportional between the hypotenuse and the part of the hypotenuse directly below the leg.
Hypotenuse =34cm
Hyp/leg = leg/part
To find leg y, part for leg y = 25cm
34/y = y/25
y^2 = 34×25 = 850
y = √850 = 29.2cm
To find leg x, part for leg x = 9cm
34/y = y/9
y^2 = 34×9 = 306
y = √306 = 17.5cm
I will attached the picture of what you are talking about here. The answer for this problem is: Yes, that they are congruent by SAS. Meaning that the triangles are congruent if their included angles and any pair of corresponding sides are equal in both triangles. In this case, the sides are both 21 cm and this will make the angle equal for both triangles, so that is why they are congruent.
Answer:
- Fantasy: 3 barrels
- Ecstasy: 1 barrel
Step-by-step explanation:
<u>Given</u>
Fantasy uses 4 lb of nuts, 3 lb of chocolate, for a profit of $50
Ecstasy uses 4 lb of nuts, 1 lb of chocolate, for a profit of $40
In stock are 16 lb of nuts, 10 lb of chocolate
<u>Find</u>
amount of each to maximize profit
<u>Solution</u>
Let x and y represent barrels of Fantasy and Ecstasy, respectively. Then the limitations on production are ...
4x +4y ≤ 16 . . . lb of nuts
3x +y ≤ 10 . . . . lb of chocolate
We want to maximize
50x +40y
The graph shows the feasible region. Its vertices are ...
(0, 4), (3, 1), (3.33, 0)
Profit is maximized at $190 when production is 3 barrels of Fantasy and 1 barrel of Ecstasy.
