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Dmitriy789 [7]
2 years ago
15

If i know a real root of f(x) = x3 -6x2 + 11x – 6 is neither 1, even, or negative, a good guess would be?

Mathematics
1 answer:
goldfiish [28.3K]2 years ago
4 0
3.
________________________
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Given circle X with radius 10 units and chord AB with length 12 units, what is the length of segment CX, which bisects the chord
andrew-mc [135]
Consider the circle with center X, as shown in the figure. 

Draw the diameter of the circle which is parallel to cherd AB, as shown in the figure.

Since the diameter and AB are parallel, then the line segment XC which bisects AB at C, will be perpendicular to AB.

SO triangle XCB is a right triangle. Thus the length of CX, by the Pythagorean theorem is  

\sqrt{ XB^{2}- CB^{2}} = \sqrt{ 10^{2}- CB^{6}}= \sqrt{100-36}= \sqrt{64}=8 units.


Answer: 8 units

7 0
2 years ago
How do i do this some one please explain
Talja [164]

Well since we already have our unit per mile.

We know that 1 mile = $3.50

And that the tow company towed the car 12 miles.

So we would have to multiply 12 by $3.50

soo..

12 x $3.50 = $42.00

So your answer is D. $42.00

4 0
2 years ago
A ballplayer catches a ball 3.4s after throwing it vertically upward. with what speed did he throw it, and what height did it re
Daniel [21]

From the equation of motion, we know,

s=ut+\frac{1}{2}at^{2}

Where s= displacement

u= initial velocity

a= gravitational force

t= time

Displacement is 0 since the ball comes back to the same point from where it was thrown.  

A = -9.8m/s^{2} since the ball is thrown upwards.

Plug the known values into the equation.

=> 0=u\left ( 3.4 \right )+\frac{1}{2}\left ( -9.81 \right )(3.4^{2})

Solving for u gives :

u= 16.67 m/ sec ....... equation (1)

At maximum height, final velocity i.e v is 0

Time take to reach the top = \frac{3.4}{2} = 1.7 sec

v^{2}=u^{2}+2as

=> 0=(16.67)^{2}+2(-9.81)(s)

Solving for s we get

s= 14.16 m


4 0
2 years ago
If x = 3 is a zero of the polynomial function f(x) = 2x3 + x2 − 25x + 12, which of the following is another zero of f(x)? ASAP
olasank [31]
If x = 3 is a solution, (x - 3) is a factor of f(x).
2x³ + x² - 25x + 12 ÷ (x - 3) [by long division] = 2x² + 7x - 4
so f(x) = (x - 3)(2x² + 7x - 4)
f(x) = (x - 3)(2x - 1)(x + 4)
so 'zeros', or more correctly solutions, are: x = 3, x = 1/2 and x = -4.
[by setting each of the factors equal to 0 and solving for x].
7 0
2 years ago
Each airline passenger and his or her luggage must be checked to determine whether he or she is carrying weapons on to the airpl
Dafna1 [17]

Answer:

a

P_k  = 0.83

b

 N_{\mu} \approx  4 \ passengers

c

T_{\lambda} =  0.5 \ minutes

Step-by-step explanation:

From the question we are told that

The average number of passengers that arrive per minute is \lambda = 10

The average number of check that can be carried out in one minute is \mu= 12

Generally the probability that a passenger will have to wait before being checked for weapons is mathematically represented as

        P_k  = \frac{\lambda }{ \mu }

=>    P_k  = \frac{10 }{ 12}

=>    P_k  = 0.83

Generally the number of passengers are waiting in line to enter the checkpoint is mathematically represented as

     N_{\mu} =  \frac{\lambda^2}{\mu (\mu -\lambda) }

=>  N_{\mu} =  \frac{10^2}{12 (12 -10) }

=>  N_{\mu} \approx  4 \ passengers

Generally the average time a passenger spend at the checkpoint is mathematically represented as

      T_{\lambda} = \frac{ \frac{\lambda}{(\mu - \lambda)} }{ \lambda}

=>   T_{\lambda} = \frac{ \frac{ 10}{(12 - 10)} }{10}

=>   T_{\lambda} =  0.5 \ minutes

5 0
1 year ago
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