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tensa zangetsu [6.8K]

2 years ago

9

The price of a pair of headphones is $39.99 before tax. Dalton bought the headphones for 30% off. He then paid 6% sales tax on t

he discounted price. Part A: How much did Dalton pay in sales tax? Show all work and steps in your solution. (5 points) Part B: What is the total amount that Dalton paid for the headphones? Show all work and steps in your solution. (5 points) DO NOT LOOK THIS UP PLS

1 answer:

dimaraw [331]2 years ago

4 0

Answer:

part A 1.68

part B 29.67

Step-by-step explanation:

First you multiply $39.99 dollars and 0.30 = $11.9970 you round this to $12.00

After you apply the discount $39.99 - $12.00 = 27.99

Next you must multiply 27.99*0.06 =1.6794 and round to 1.68 to get tax

Last you add $27.99 and 1.68 to get a total of $29.67 for the headphones

Plz give brainliest i didnt look it up.

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If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe

Natalka [10]

Answer:

They encircle the planet $3.76\times 10^{11}$ times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is $6.022\times 10^{23}$

Thus, the number of dust particles is:

$2.5\times 6.022\times 10^{23}=15.055\times 10^{23}$

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: $10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m$

If we line up the particles the distance they could cover is:

$15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}$

Circumference in meters:

$40,076km\times \frac{1000m}{1km}=40,076,000 m$

Therefore,

$\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}$

Hence, they encircle the planet $3.76\times 10^{11}$ times.

8 0

1 year ago

Given E = I × R and P = E × I, select the formula that will solve for E when only R and P are known.

stiv31 [10]

$E = \left\{(a,b) \mid a \in I \text{ and } b \in R \right\}$ , $P = \left\{(a,b) \mid a \in E \text{ and } b \in R \right\}$ but we cannot solve for the set $E$ because we are missing information.

3 0

1 year ago

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With food prices becoming a great issue in the world; wheat yields are even more important. Some of the highest yielding dry lan

Rzqust [24]

Answer:

Option E) 61.6

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 100 bushels per acre

Standard Deviation, σ = 30 bushels per acre

We assume that the distribution of yield is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(X>x) = 0.90

We have to find the value of x such that the probability is 0.90

P(X > x)

$P( X > x) = P( z > \displaystyle\frac{x - 100}{30})=0.90$

$= 1 -P( z \leq \displaystyle\frac{x - 100}{30})=0.90$

$=P( z \leq \displaystyle\frac{x - 100}{30})=0.10$

Calculation the value from standard normal table, we have,

$P(z$

$\displaystyle\frac{x - 100}{30} = -1.282\\x = 61.55 \approx 61.6$

Hence, the yield of 61.6 bushels per acre or more would save the seed.

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1 year ago

What's 3/4 times 7/9 in simplest form

Alexxandr [17]

3/4 times 7/9:

First, we must use the rule for multiplying fraction. The rule is: a/b times c/d = ac/ bd. Let's substitute our problem into that formation.
$\frac{3 \times 7}{4 \times 9}$

Second, we can now simplify. (3 times 7 = 21) and (4 times 9 = 36).
$\frac{21}{36}$

Third, since our fraction is not in the simplest form, we can simplify it down by listing the factors of both the numerator and denominator and then finding the greatest common factor (GCF).

Factors of 21: 1, 3, 7, 21
Factors of 36: 1, 2, 3, 4, 6, 9, 12, 18, 36

The GCF is 3, since only 1 and 3 were the common factors and since 3 is the greatest common factor.

Fourth, now we can divide our numerator (21) and denominator (36) by our recently found GCF which was 3.

$21 \div 3 = 7 \\ 36 \div 3 = 12$

Our new fraction in its simplest form is 7/12.

Answer in fraction form: $\fbox {7/12}$
Answer in decimal form: $\fbox {0.5833}$

7 0

2 years ago

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Two parallel lines are intersected by a third line so that angles 1 and 5 are congruent. 2 parallel horizontal lines are interse

densk [106]

Answer:

"They are supplementary" ⇒ last answer

Step-by-step explanation:

* <em>Look to the attached figure</em>

- Two parallel horizontal lines are intersected by a third line

- The angles formed form intersection are labeled on the figure

- From the two parallel lines and

∠5 ≅ ∠1 ⇒ corresponding angles

m∠5 = m∠1

- A linear pair is two angles that are adjacent and form a line and

they are supplementary

∠1 and ∠3 form a line

∠1 and ∠3 are linear pair

* <em>lets prove that ∠3 and ∠5 are supplementary</em>

∵ m∠1 = m∠5 ⇒ corresponding angles

∵ ∠1 and ∠3 form a linear pair

∵ Linear pair are supplementary

∴ m∠1 + m∠3 = 180°

- By substitute ∠1 by ∠5

∴ m∠5 + m∠3 = 180

∴ ∠5 and ∠3 are supplementary

* The true statement is "They are supplementary"

8 0

1 year ago

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