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gladu [14]
2 years ago
12

Write an absolute value equation to satisfy the given solution set shown on a number line.

Mathematics
1 answer:
aivan3 [116]2 years ago
8 0

Answer: IX - 4I ≤ 4

Step-by-step explanation:

In the numer line we can see that our possible values of x are in the range:

0 ≤ x ≤ 8

And we want to find an absolute value equation such that this set is the set of possible solutions.

An example can be:

IX - 4I ≤ 4

To construct this, we first find the midpoint M of our set, in this case is 4.

Then we write:

Ix - MI  ≤ IMI

Notice that i am using the minor and equal sign, this is because the black dots means that the values x = 0 and x = 8 are included, if the dots were empty dots, it would be an open set and we should use the <  > signs.

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Translate and solve: seventy-eight times n is at least 312.
RideAnS [48]

It translates to 78n \ge 312 which solves to n \ge 4 after dividing both sides by 78. This means n is equal to 4 or it can be larger than 4.

7 0
2 years ago
Factor the polynomial expression 15x^2 - 2x - 8
AVprozaik [17]

Answer:

(3 x + 2) (5 x - 4)

Step-by-step explanation:

Factor the following:

15 x^2 - 2 x - 8

Factor the quadratic 15 x^2 - 2 x - 8. The coefficient of x^2 is 15 and the constant term is -8. The product of 15 and -8 is -120. The factors of -120 which sum to -2 are 10 and -12. So 15 x^2 - 2 x - 8 = 15 x^2 - 12 x + 10 x - 8 = 5 x (3 x + 2) - 4 (3 x + 2):

5 x (3 x + 2) - 4 (3 x + 2)

Factor 3 x + 2 from 5 x (3 x + 2) - 4 (3 x + 2):

Answer: (3 x + 2) (5 x - 4)

4 0
2 years ago
The perimeter of the base of a regular quadrilateral prism is 60 cm, the area of one of the lateral faces is 105 cm2.
yawa3891 [41]

For a better understanding of the solution, please follow the diagram in the attached file.

A regular quadrilateral is basically a square.

So, if the base of the prism has a perimeter of 60 cm, then the length of the side of the square will be \frac{60}{4}=15 cm. It is shown of the diagram.

Now, from the diagram, it is clear that the lateral face area, which is given as 105 cm^2, is the product of the side of the square, which is known, and the unknown height, let us call it h. Thus, we will get the following equation:

15\times h=105

\therefore h=\frac{105}{15}=7 cm

This is depicted on the diagram.

Now, all our required parameters are in place. Thus, let us find what has been asked.

<u>SURFACE AREA</u>

Surface Area (SA) will be the sum of the areas of the two bases (squares) and the areas of the four lateral faces.

Since the side of one square base is 15 cm, therefore, the area of one square base will be 15^2.

Likewise, the area of one lateral surface is actually the area of a rectangle with length 15 cm and height 7 cm. Thus, it's area will be given as: 15\times 7.

Thus, our equation will be:

SA=2\times 15^2+4\times 15\times 7=870 cm^2

Therefore, Surface Area=870 cm^2

<u>VOLUME OF THE PRISM</u>

The volume of the prism will simply be the area of the base times the height of the prism.

Thus, the volume is:

Volume=15^2\times 7=1575 cm^3


5 0
2 years ago
Examine the steps used to solve the equation.
Elina [12.6K]

Answer:

see below

Step-by-step explanation:

12.5x − 10.2 = 3(2.5x + 4.2) - 6  

Use the distributive property to distribute the 3

12.5x − 10.2 = 7.5x + 12.6 − 6  

Combine like terms

12.5x − 10.2 = 7.5x + 6.6  

Add 10.2 to each side of the equation by using the addition property of equality

12.5x = 7.5x + 16.8

Subtraction 7.5x from each side of the equation by using the subtraction property of equality

5x = 16.8  

Divide by 5 on each side by using the division property of equality

x = 3.36

6 0
2 years ago
Read 2 more answers
Zucchini plants require 9 square feet around each plant.
MrRa [10]
The area of square TUVW = 3×3 = 9 square units

1 square unit = 4 head lettuces
9 square units = 9×4 = 36 lettuces

Area of plot QRST = length × width = 12×6 = 72 square units

36 vegetables for every 9 square units
We have 72÷9 = 8 lots of 9 square units

Total vegetable = 8 × 36 = 288 vegetables

We can have 8 different vegetables, each type can have 36 vegetables
4 0
2 years ago
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