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GREYUIT [131]
2 years ago
6

Examine the steps used to solve the equation.

Mathematics
2 answers:
Elina [12.6K]2 years ago
6 0

Answer:

see below

Step-by-step explanation:

12.5x − 10.2 = 3(2.5x + 4.2) - 6  

Use the distributive property to distribute the 3

12.5x − 10.2 = 7.5x + 12.6 − 6  

Combine like terms

12.5x − 10.2 = 7.5x + 6.6  

Add 10.2 to each side of the equation by using the addition property of equality

12.5x = 7.5x + 16.8

Subtraction 7.5x from each side of the equation by using the subtraction property of equality

5x = 16.8  

Divide by 5 on each side by using the division property of equality

x = 3.36

liberstina [14]2 years ago
5 0

Answer:

Step 1 distributive property

Step 2 combining like terms

Step 3 addition property

Step 4 subtraction property

Step 5 division property

Step-by-step explanation:

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Merrill Lynch Securities and Health Care Retirement Inc. are two large employers in downtown Toledo, Ohio. They are considering
ratelena [41]

Answer:

Step-by-step explanation:

We would determine the mean an standard deviation first

Mean = (107 + 92 + 97 + 95 + 105 + 101 + 91 + 99 + 95 + 104)/10 = 98.6

Standard deviation = √(summation(x - mean)/n

n = 10

Summation(x - mean) = (107 - 98.6)^2 + (92 - 98.6)^2 + (97 - 96.6)^2 + (95 - 98.6)^2 + (105 - 98.6)^2 + (101 - 98.6)^2 + (91 - 98.6)^2 + (99 - 98.6)^2 + (95 - 98.6)^2 + (104 - 98.6)^2 = 274

Standard deviation = √(274/10) = 5.23

The confidence interval is used to determine the range of values that could possibly contain a population parameter (population mean)

Confidence interval is written in the form,

(Point estimate - margin of error, Point estimate + margin of error)

The sample mean, x is the point estimate for the population mean.

We will use the t distribution because the sample size is small and the population standard deviation is not given.

Degree of freedom, df = 10 - 1 = 9

α = 1 - 0.99 = 0.01

z α/2 = 0.01/2 = 0.005

The area to the right of z 0.005 is 0.005 and the area to the left of z0.005 is 1 - 0.005 = 0.995. Using the t distribution table,

z = 3.25

Margin of error = z × s/√n

Where

s = sample standard Deviation = 5.23

Margin of error = 3.25 × 5.23/√10 = 5.38

Confidence interval = sample mean(point estimate) ± z × σ/√n

The lower boundary of the confidence interval is

98.6 - 5.38 = 93.22

The upper boundary of the confidence interval is

98.6 + 5.38 = 103.98

We estimate with 99% confidence that the mean weekly child care cost of their employees is between $93.22 and $103.98

Also,

99% of the confidence intervals constructed in this way would contain the true value for the population mean of mean weekly child care cost of their employees.

6 0
2 years ago
Compute the requested value. Choose the correct answer.
Fiesta28 [93]

Original price of the item = $14.95

Price after discount = $13.79

Discount offered = original price - price after discount = 14.95- 13.79 = $1.16

Now let us find the percentage of discount offered.

Percentage discount is given by the formula:

Percentage discount = \frac{MP-SP}{MP}*100

Where MP= Marked price= original price

SP= selling price= price after discount

Percentage discount = \frac{1.16}{14.95}*100

Percentage discount = 7.759 %

7 0
1 year ago
Read 2 more answers
Unit 3 parallel and perpendicular lines homework 4 parallel line proofs
Alex17521 [72]

Answer:

1) c ║ d by consecutive interior angles theorem

2) m∠3 + m∠6 = 180° by transitive property

3) ∠2 ≅ ∠5 by definition of congruency

4) t ║ v                                    {}                   Corresponding angle theorem

5) ∠14 and ∠11  are supplementary         {}  Definition of supplementary angles

6) ∠8 and ∠9  are supplementary    {}        Consecutive  interior angles theorem

Step-by-step explanation:

1) Statement                                {}                                     Reason

m∠4 + m∠7 = 180°                                 {}   Given

m∠4 ≅ m∠6                                {}              Vertically opposite angles

m∠4 = m∠6                               {}                Definition of congruency

m∠6 + m∠7 = 180°                                {}    Transitive property

m∠6 and m∠7 are supplementary     {}     Definition of supplementary angles

∴ c ║ d                               {}                       Consecutive interior angles theorem

2) Statement                                {}                                     Reason

m∠3 = m∠8                                 {}           Given

m∠8 + m∠6 = 180°                {}                 Sum of angles on a straight line

∴ m∠3 + m∠6 = 180°               {}               Transitive property

3) Statement                                {}                                     Reason

p ║ q                                 {}                    Given

∠1 ≅ ∠5                               {}                  Given

∠1 = ∠5                               {}                   Definition of congruency

∠2 ≅ ∠1                               {}                  Alternate interior angles theorem

∠2 = ∠1                               {}                   Definition of congruency

∠2 = ∠5                                  {}               Transitive property

∠2 ≅ ∠5                                  {}              Definition of congruency.

4) Statement                                {}                                     Reason

∠1 ≅ ∠5                                  {}                Given

∠3 ≅ ∠4                               {}                  Given

∠1 = ∠5                               {}                   Definition of congruency

∠3 = ∠4                               {}                  Definition of congruency

∠5 ≅ ∠4                               {}                 Vertically opposite angles

∠5 = ∠4                               {}                  Definition of congruency

∠5 = ∠3                                  {}               Transitive property

∠1 = ∠3                                  {}                Transitive property

∠1 ≅ ∠3                                  {}                Definition of congruency.

t ║ v                                    {}                   Corresponding angle theorem

5) Statement                                {}                                     Reason

∠5 ≅ ∠16                                  {}              Given

∠2 ≅ ∠4                               {}                  Given

∠5 = ∠16                               {}                  Definition of congruency

∠2 = ∠4                               {}                   Definition of congruency

EF ║ GH                               {}                  Corresponding angle theorem

∠14 ≅ ∠16                               {}                Corresponding angles

∠14 = ∠16                               {}                 Definition of congruency

∠5 = ∠14                                  {}               Transitive property

∠5 + ∠11 = 180°                {}                       Sum of angles on a straight line

∠14 + ∠11 = 180°                                {}      Transitive property

∠14 and ∠11  are supplementary         {}  Definition of supplementary angles  

6) Statement                                {}                                     Reason

l ║ m                                 {}                      Given

∠4 ≅ ∠7                               {}                  Given

∠4 = ∠7                               {}                   Definition of congruency

∠2 ≅ ∠7                               {}                  Alternate angles

∠2 = ∠7                               {}                   Definition of congruency

∠2 = ∠4                                  {}               Transitive property

∠2 ≅ ∠4                               {}                  Definition of congruency

∠2 and ∠4 are corresponding angles   {} Definition

DA ║ EB                               {}                  Corresponding angle theorem

∠8 and ∠9  are consecutive  interior angles    {} Definition

∠8 and ∠9  are supplementary    {}        Consecutive  interior angles theorem.

6 0
2 years ago
Nathan flew 3,547 miles from Canada to California during the first part of his trip. He flew 2,567 miles from California to Hawa
AURORKA [14]

Difference in the number of miles Nathan flew between the first and second parts of his trip is 980 miles

<em><u>Solution:</u></em>

Given that Nathan flew 3,547 miles from Canada to California during the first part of his trip

He flew 2,567 miles from California to Hawaii during the second part of his trip

Therefore,

first part of his trip = 3547 miles

second part of his trip = 2567 miles

Difference in the number of miles Nathan flew between the first and second parts of his trip is given as:

difference = first part of his trip - second part of his trip

difference = 3547 - 2567 = 980

Therefore, the difference in number is 980 miles

4 0
2 years ago
You and three friends own a paint shop. The shop's profit was $536 in the first month. You always divide the profits equally. In
alexandr1967 [171]
C.  $360


$224x4=896 (total profit)

$896 (total) - $536 (first month profit) = $360 (second month profit)
4 0
2 years ago
Read 2 more answers
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