Let's simplify step-by-step.
<span><span>0.2<span>(<span><span>3b</span>−<span>15c</span></span>)</span></span>+<span>6c
</span></span>Distribute:<span>=<span><span><span><span>(0.2)</span><span>(<span>3b</span>)</span></span>+<span><span>(0.2)</span><span>(<span>−<span>15c</span></span>)</span></span></span>+<span>6c
</span></span></span><span>=<span><span><span><span>0.6b</span>+</span>−<span>3c</span></span>+<span>6c
</span></span></span>Combine Like Terms:
<span>=<span><span><span>0.6b</span>+<span>−<span>3c</span></span></span>+<span>6c
</span></span></span><span>=<span><span>(<span>0.6b</span>)</span>+<span>(<span><span>−<span>3c</span></span>+<span>6c</span></span>)
</span></span></span><span>=<span><span>0.6b</span>+<span>3<span>c</span></span></span></span>
Hello here is a solution :
The mean is 36 and the standard deviation is 5.02.
The mean is given by
μ = np = 120*0.3 = 36.
The standard deviation is given by
σ = √(n*p*(1-p)) = √(120*0.3*0.7) = √25.2 = 5.02.
