You'll find it easier to understand if you illustrate the problem as what is shown in the attached picture. From the illustration and the problem description, two equations can be formulated:
HJ = 2JK
HJ + JK = HK
2JK + JK = 78
3JK = 78
JK = 78/3
JK = 26
Answer:
The probability mass of X is 0.03
Step-by-step explanation:
If we set the winning requirement of your heads and my tails then the occurring possibility of both is 1/2 or 0.5.
Hence let us make a graph and use the figures to calculate the all the probabilities of you getting a heads.
Where X represents the number of dollars won during the flip of the coin, probability of heads represent the chances of occurrence of the value and of winning the dollars.
The probability of winning start to drop as the winning amount increases.
X 0 1 2 3 4 5
Probability of Heads 0 0.50 0.25 0.13 0.06 0.03
To solve the quadratic equation given by 0=x^2-9x-20, we use the quadratic formula given by:
x=[-b+\- sqrt(b^2-4ac)]/(2a)
where,
a=1,b=-9,c=-20
thus substituting the above values into our formula we get:
x=[9+\-sqrt(9^2-4(-20*1))/(2*1)
x=[9+\-sqrt(161)]/2
x=[9+sqrt161]/2 or x=[9-sqrt161]/2
Car value at the time of purchase $15, 250 (2012)
Rate of depreciation 7.5%
1) y = 15250 ( 1- 0.075)^x
y = 15250 (0.925)^x (x tis the number of years that passed since purchase)
2) y = 15250 * ( 0.925)^8 = 8173.42