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Sonja [21]
2 years ago
11

PLEASE HELP ME School rules permit no fewer than 2 teachers per 25 students. There are at least 245 students enrolled in the sch

ool. If x represent teachers and y represents students, which system of linear inequalities can be used to determine the possible number of teachers and students at the school?
a)2y ≥ 25x and y ≥ 245
b)2y ≤ 25x and y ≥ 245
c)25y ≤ 2x and y ≥ 245
d)25y ≥ 2x and y ≥ 245
Mathematics
2 answers:
Simora [160]2 years ago
9 0
Its acualy b man sry 
11111nata11111 [884]2 years ago
4 0

Answer: b) 2y\leq 25x and y\geq 245


Step-by-step explanation:

If y represents students .

"There are at least 245 students enrolled in the school" gives

y\geq 245

Since school rules permit no fewer (atleast) than 2 teachers per 25 students.

Thus the rate of teachers=\frac{x}{y}\geq \frac{2}{25}

\\\Rightarrow25x\geq 2y

Hence, b is the right option.

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Samuel and Hayden solved the system of equations –6x – 6y = –6 and 7x + 7y = 7. Samuel says there are infinitely many solutions,
yawa3891 [41]

Answer:

Samuel is correct i.e  there are infinitely many solutions

Step-by-step explanation:

Given that Samuel and Hayden solved the system of equations –6x – 6y = –6 and 7x + 7y = 7. we have to find that whether the system of equations has infinitely many solutions or not.

A system of linear equations has infinite solutions if the graphs are the exact same line i.e the the equations are equivalent.

The first equation:  –6x – 6y = –6 ⇒ x+y=1 ⇒ y=-x+1

∴ the slope of its line is -1 and the y-intercept is 1

The second equation:  7x + 7y = 7 ⇒  x+y=1 ⇒ y=-x+1

∴ the slope of its line is -1 and the y-intercept is 1.

Here, we get the equation which has the same slope and y-intercept as that of the first equation.

In other words, the two equations are represented by the same line. This implies that the lines intersect infinitely many times, or that the system has infinitely many solutions.

Hence, Samuel is correct.

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2 years ago
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One of the byproducts of nuclear power generation is Uranium-233. Uranium is decaying at a constant 57% rate per day. If 3,820 p
yanalaym [24]
Given that the decay rate of the uranium is given to be 57%, this means that on the second day only 43% of the Uranium-233 will be left. The equation therefore, that will allow us to answer the question is that,
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where A(t) is the amount after n days, A(0) is the original amount, r is the decimal equivalent of the rate and n is the number of days. Substituting the known values,
                                  A(t) = (3,820 pounds)*(1-0.57)^15
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This is unfortunately not found in the choices. 
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2 years ago
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12,400 x one and one fifth = ________. Will the product of this equation be less than or greater than 12,400? Explain your reaso
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Answer:

Your answer would be 14,880, so it would be greater than 12,400.

12,400 * 1 1/5 = 14,880

3 0
2 years ago
Lesson 1-1: The periodic comet named Johnson has been seen at every return since its discovery in 1949, as shown in the table be
stiks02 [169]

Answer:

Step-by-step explanation:

Occurrence                 Year seen          Difference

1                                      1949                       -  

2                                     1956               1956 - 1949 = 7

3                                     1963               1963 - 1956 = 7

4                                     1970                1970 - 1963 = 7

Difference between each successive term of year seen = 7 years

Therefore, there is a common difference of 7 years between each successive term.

Function defining the year seen will be a linear function and will increase in the same pattern. (multiple of 7 years)

2017 - 1970 = 47 (It's not the multiple of 7)

2018 - 1970 = 48 (It's not the multiple of 7)

2019 - 1970 = 49 (multiple of 7)

2020 - 1970 = 50 (It's not the multiple of 7)

Therefore, comet will be seen next in 2019.

Option (C) will be the answer.

If a person is born in 2005

Then difference between 2005 and 1949 = 56 years

Number of times comet seen after 1949 = \frac{56}{7}=8 times

Total number of comet seen in the lifetime = 8 times

5 0
2 years ago
Identify the 12th term of the arithmetic sequence in which a7 = 40 and a18 = 106.
Lady_Fox [76]

we are given

airthematic sequence

we can use nth term formula

a_n=a_1+(n-1)d

n is number of terms

an is nth term

d is common difference

a1 is first term

We are given

a7=40

we can use it

a_7=a_1+(7-1)d

40=a_1+6d

a_1+6d=40

a18 = 106

a_1_8=a_1+(18-1)d

a_1+17d=106

we can subtract both equations

a_1+17d-a_1-6d=106-40

11d=66

d=6

now, we can find a1

a_1+6d=40

we can plug d=6

a_1+6*6=40

a_1=4

12th term:

a_1_2=a_1+(12-1)d

now, we can plug values

a_1_2=4+(12-1)*6

a_1_2=4+66

a_1_2=70

so, 12th term is 70...........Answer

3 0
2 years ago
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