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Colt1911 [192]
2 years ago
14

The advertised claim for batteries for cell phones is set at 48 operating hours with proper charging procedures. A study of 5000

batteries is carried out and 15 stop operating prior to 48 hours.
Do these experimental results support the claim that less than 0.2 percent of the company’s batteries will fail during the advertised time period (assuming proper charging procedures were followed)?

Use a hypothesis testing procedure with α = 0.01. State H0 and H1, test statistic, critical value(s), critical (rejection) region, p-value, and conclusion. Hint: Here, H1 is something against what the company claims.
Mathematics
1 answer:
Komok [63]2 years ago
8 0
Yes cghhfdghgdfggfffdgghhg
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What is the factored form of the binomial expansion 125x^3 + 525x^2 + 735x + 343?
yarga [219]

Answer:

Step-by-step explanation:

1. regroup terms

125x^3+343+525x^2+735x

2. Rewrite 125x^3 as  (5x)^3 and 343 as 7^3

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3. Since both terms are perfect cubes, factor using the sum of cubes formula, a^3+b^3 = (a+b)(a^2-ab+b^2), where a=5x and b=7

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4. Factor 105x out of 525x^2+735x

(5x+7)(25x^2-35x+49)+105x(5x+7)

5. Regroup

(5x+7)(25x^2-35x+49+105x)

(5x+7)(25x^2+70x+49)

6. Factor again

(5x+7)(5x+7)^2

(5x+7)^3

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