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Fofino [41]
2 years ago
5

Eden is cutting two triangular tiles for her bathroom. She needs the tiles to be congruent but is not sure she is cutting them t

hat way. Eden has ensured that one side of both tiles is congruent. Which pair of sides would Eden need to compare in order to make sure the triangles are congruent by HL? triangle ABC with coordinates A at 1 comma 4, B at 2 comma 4, C at 1 comma 1, and a right angle symbol at A and length of AC of 3 units, triangle EFD with coordinates E at 2 comma negative 2, F at one comma negative 2, D at 2 comma 1 and a right angle symbol at E with length of ED of 3 units segment AC and segment EF segment AC and segment FD segment BC and segment EF segment BC and
Mathematics
2 answers:
Elis [28]2 years ago
4 0

Answer:

I think its BC and FD

Montano1993 [528]2 years ago
4 0

Answer:

<h2>Segment FD and segment BC.</h2>

Step-by-step explanation:

The HL postulate refers to corresponding Hypothenuse-Leg postulate which is used to demonstrate congruence between two right triangles. These postulate only need two evidences to prove because right triangles already have a congruent angle, so it's like using Side-Angle-Side Postulate.

So, in the given problem, we have to triangles, ABC and EFD, which are both right triangles, and we already have one side or leg congruent: AC \cong DE

So, to demonstrate the congruence using HL postulate, we just have to compare both hypothenuses and see if they are congruent: FD \cong BC

Therefore, the asnwer is "Eden needs to compare segment FD and segment BC, to demonstrate the congruence by HL postulate.

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A car was purchased for $25,000. Research shows that the car has an average yearly depreciation rate of 18.5%. Create a function
vitfil [10]

Answer:

V(t) = 25000 * (0.815)^t

The depreciation from year 3 to year 4 was $2503.71

Step-by-step explanation:

We can model V(t) as an exponencial function:

V(t) = Vo * (1+r)^t

Where Vo is the inicial value of the car, r is the depreciation rate and t is the amount of years.

We have that Vo = 25000, r = -18.5% = -0.185, so:

V(t) = 25000 * (1-0.185)^t

V(t) = 25000 * (0.815)^t

In year 3, we have:

V(3) = 25000 * (0.815)^3 = 13533.58

In year 4, we have:

V(4) = 25000 * (0.815)^4 = 11029.87

The depreciation from year 3 to year 4 was:

V(3) - V(4) = 13533.58 - 11029.87 = $2503.71

7 0
2 years ago
The US Department of Health and Human Services wants to know whether the national healthcare system is achieving its goals in Vi
Vlad [161]

Answer:

Part. B

bc it was 71%

6 0
2 years ago
Read 2 more answers
Oil flows back and forth between a small and large tank. When oil is moving into the large tank, the flow rate is
Vladimir [108]

Answer:

so the answer is =6187200

Step-by-step explanation:

600 divide by 4=150

150 multiply 32=4800

4800 divided by 1289=6187200.

3 0
2 years ago
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According to a study in a medical journal, 202 of a sample of 5,990 middle-aged men had developed diabetes. It also found that m
tekilochka [14]

Answer:

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Has diabetes.

Event B: Is very active.

Probability of having diabetes:

To find this probability, we take in consideration that:

It also found that men who were very active (burning about 3,500 calories daily) were a fourth as likely to develop diabetes compared with men who were sedentary. Assume that one-fifth of all middle-aged men are very active, and the rest are classified as sedentary.

So the probability of developing diabetes is:

x of 4/5 = x of 0.8(not active)

x/4 = 0.25x of 1/5 = 0.2(very active). So

P(A) = 0.8x + 0.25*0.2x = 0.85x

Probability of developing diabetes while being very active:

0.25x of 0.2. So

P(A \cap B) = 0.25x*0.2 = 0.05x

What is the probability that a middle-aged man with diabetes is very active?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.05x}{0.85x} = \frac{0.05}{0.85} = 0.0588

0.0588 = 5.88% probability that a middle-aged man with diabetes is very active

4 0
2 years ago
G is the centroid of triangle ABC.<br> What is the length of GF?<br><br> ___ units
Ksenya-84 [330]
So the longer lines are 2x longer than the shorter lines
Look at line segment BD
40 is 2x as long as 9x+2
In order to make the equation true, multiple 9x+2 by 2
So, you should get:
40=18x+4
36=18x
x=2
Plug the 2 into 19X+14, and divide that answer by 2, because GF is 2x smaller than AG
19x+14
19(2)+14
52
52/2=26
Hope this helps!!

4 0
2 years ago
Read 2 more answers
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