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Vlada [557]
2 years ago
8

Well, Bruh Deer got away that time. He gone! And when he ready to cross that river again, he look around for Bruh Alligator firs

t. . . . And Bruh Deer sneak close to the river to take a chance on gettin across. Before Bruh Deer can wet he hoof, Bruh Alligator see him and he slip off the bank to go meet Bruh Deer. How Bruh Deer gone get across go see his family? —“Bruh Alligator and Bruh Deer,” Virginia Hamilton.
Use context clues to figure out the meaning of the phrase “wet he hoof.” Write one to three sentences explaining your definition.
Mathematics
2 answers:
forsale [732]2 years ago
7 0

Answer:

the sample answer was..." The phrase "wet he hoof" means to get his foot wet. The author describes the setting with Bruh Deer at the edge of the river trying to cross. He sees Bruh Alligator, so he does not have a chance to get in the water, not even with one foot. These context clues show that the words probably mean "get his foot wet."

scoray [572]2 years ago
5 0

Sample Answer:

The phrase "wet he hoof" means to get his foot wet. The author describes the setting with Bruh Deer at the edge of the river trying to cross. He sees Bruh Alligator, so he does not have a chance to get in the water, not even with one foot. These context clues show that the words probably mean "get his foot wet."

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For the last part, you have to find where f'(t) attains its maximum over 0\le t\le8. We have

f'(t)=-6\sin3t+6\cos2t

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f''(t)=-18\cos3t-12\sin2t

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-18\cos3t-12\sin2t=0

3\cos3t+2\sin2t=0

3(\cos^3t-3\cos t\sin^2t)+4\sin t\cos t=0

\cos t(3\cos^2t-9\sin^2t+4\sin t)=0

\cos t(12\sin^2t-4\sin t-3)=0

So either

\cos t=0\implies t=\dfrac{(2n+1)\pi}2

or

12\sin^2t-4\sin t-3=0\implies\sin t=\dfrac{1\pm\sqrt{10}}6\implies t=\sin^{-1}\dfrac{1\pm\sqrt{10}}6+2n\pi

where n is any integer. We get 8 solutions over the given interval with n=0,1,2 from the first set of solutions, n=0,1 from the set of solutions where \sin t=\dfrac{1+\sqrt{10}}6, and n=1 from the set of solutions where \sin t=\dfrac{1-\sqrt{10}}6. They are approximately

\dfrac\pi2\approx2

\dfrac{3\pi}2\approx5

\dfrac{5\pi}2\approx8

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2\pi+\sin^{-1}\dfrac{1+\sqrt{10}}6\approx7

2\pi+\sin^{-1}\dfrac{1-\sqrt{10}}6\approx6

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2 years ago
The diameter of Circle Q terminates on the circumference of the circle at (0,3) and (0,-4). Write the equation of the circle in
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First, determine the center of the circle by getting the midpoint of the points given for the circumference.
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Then, we get the radius by determining the distance from either of the circumferential point to the center. 
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The equation for the circle would be,
                        x² + (y + 0.5)² = 7²
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2 years ago
On a coordinate plane, 5 trapezoids are shown. Trapezoid L M N P is in quadrant 2 and has points (negative 5, 1), (negative 5, 4
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