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uysha [10]
2 years ago
8

The probabilities of the orphaned pets in six cities' animal shelters being different types of animals are given in the table. I

f a randomly selected orphaned pet in a St. Louis animal shelter is a dog, what is the probability that it is a mastiff?
City Cat Dog−Lhasa Apso Dog−Mastiff Dog−Chihuahua Dog−Collie
Austin 24.5% 2.76% 2.86% 3.44% 2.65%
Baltimore 19.9% 3.37% 3.22% 3.31% 2.85%
Charlotte 33.7% 3.25% 3.17% 2.89% 3.33%
St. Louis 43.8% 2.65% 2.46% 3.67% 2.91%
Salt Lake City 28.9% 2.85% 2.78% 2.96% 2.46%
Orlando 37.6% 3.33% 3.41% 3.45% 2.78%
Total 22.9% 2.91% 2.68% 3.09% 2.58%
15.30%
18.15%
21.04%
21.84%
Mathematics
2 answers:
olga2289 [7]2 years ago
5 0
Given the table below showing t<span>he probabilities of the orphaned pets in six cities' animal shelters being different types of animals.

</span>
   City          Cat          Dog        Dog        Dog       <span>Dog                                      
                         −Lhasa Apso −Mastiff −Chihuahua −Collie
Austin       24.5%      2.76%    2.86%     3.44%    2.65%
Baltimore 19.9%      3.37%    3.22%     3.31%    2.85%
Charlotte  33.7%     3.25%     3.17%     2.89%    3.33%
St. Louis  43.8%     2.65%     2.46%     3.67%    2.91%
Salt Lake
City          28.9%     2.85%     2.78%     2.96%    2.46%
Orlando   37.6%     3.33%     3.41%     3.45%    2.78%
Total        22.9%     2.91%     2.68%     3.09%    2.58%</span><span>

Condtional probability </span><span>is a measure of the probability of an event given that another event has occurred. If the event of interest is A and the event B is known or assumed to have occurred, "the conditional probability of A given B", or "the probability of A under the condition B", is usually written as P(A|B).

The probability of A given B, is given by
P(A|B)= \frac{P(A\cap B)}{P(B)}

From the table, the probability that an </span>orphaned pet in a St. Louis animal shelter is a mastiff dog is 2.46% and the probability that <span>an <span>orphaned pet in a St. Louis animal shelter is a dog is 2.91% + 2.68% + 3.09% + 2.58% = 11.26%</span>

The probability that a randomly selected orphaned pet in a St. Louis animal shelter is a mastiff given that it is a dog, is given by
\frac{P(St. \, Louis\, and\, dog-mastiff)}{P(dog)} = \frac{2.46}{11.26} \times100\%=21.85\%</span>
wariber [46]2 years ago
4 0

Answer:

The correct answer is A. 21.04%. I just took the test.

Step-by-step explanation:

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7 0
2 years ago
Noah received a $500 signing bonus when he accepted a job as a paralegal. If he makes $28 an hour, which equation models Noah's
sveta [45]
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The answer is A
4 0
2 years ago
If a(x) = 3x + 1 and b (x) = StartRoot x minus 4 EndRoot, what is the domain of (b circle a) (x)?
kiruha [24]

Answer:

[1,\infty)

Step-by-step explanation:

b(x)=\sqrt{x-4}

a(x)=3x+1

Since we want to know the domain of (b \circ a)(x), let's first consider the domain of the inside function, that is, that of a(x)=3x+1. Every polynomial function has domain all real numbers.

So we can plug anything for function a and get a number back.

Now the other function is going to be worrisome because it has a square root. You cannot take square root of negative numbers if you are only considering real numbers which that is the case with most texts.

Let's find (b \circ a)(x) and simplify now.

(b \circ a)(x)

b(a(x))

b(3x+1)

\sqrt{(3x+1)-4}

\sqrt{3x+1-4}

\sqrt{3x-3}

Now again we can only square root positive or zero numbers so we want 3x-3 \ge 0.

Let's solve this to find the domain of (b \circ a)(x).

3x-3 \ge 0

Add 3 on both sides:

3x \ge 3

Divide both sides by 3:

x \ge 1

So we want x to be a number greater than or equal to 1.

The option that says this is [1,\infty)

-------------------------------

Give an example why option A fails:

A number in the given set is -2.

a(x)=3x+1

b(x)=\sqrt{x-4}

So a(-2)=3(-2)+1=-6+1=-5 and b(-5)=\sqrt{-5-4}=\sqrt{-9} \text{ which is not real}.

Give an example why option B fails:

A number in the given set is 0.

a(x)=3x+1

b(x)=\sqrt{x-4}

So a(0)=3(0)+1=0+1=1 and b(1)=\sqrt{1-4}=\sqrt{-3} \text{ which is not real}.

Give an example why option D fails:

While all the numbers in set D work, there are more numbers outside that range of numbers that also work.

A number not in the given set that works is 3.

a(x)=3x+1

b(x)=\sqrt{x-4}

So a(3)=3(3)+1=9+1=10 and b(1)=\sqrt{10-4}=\sqrt{6} \text{ which is real}.

4 0
2 years ago
Read 2 more answers
Hi. Please I need help with this :
ki77a [65]

Answer:

1.79553

Step-by-step explanation:

Step 1: Write expression

log₁₀(√(69.5² - 30.5²))

Step 2: Evaluate square root

log(√(4830.25 - 930.25))

log(√3900)

log(62.45)

Step 3: Find log

log₁₀ (or log)

log(62.45) = 1.79553

-------------------------------------

To use the table method. we find values that are easily evaluated by log₁₀

log₁₀(10) = 1

log₁₀(50) = 1.69897

log₁₀(100) = 2

So we know that log₁₀(62.45) is between 1 and 2 and greater that 1.69897.

3 0
2 years ago
In how many ways can you put seven marbles in different colors into two jars? Note that the jars may be empty.
ahrayia [7]

Answer:

128

Step-by-step explanation:

You have two jars and seven marbles.

You do 2^{7}.

That is 128

3 0
2 years ago
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