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Lelechka [254]
2 years ago
5

The image of a triangle after it has been dilated with a center of dilation at the origin has vertices at A prime(12, –6), B pri

me(–24, –12), and C prime. If the pre-image of B prime, point B, has coordinates of (–18, –9) and the pre-image of C prime, point C, has coordinates of (–13.5, 18), which statements are true? Check all that apply. The coordinates of C prime are (27, 18). The coordinates of C prime are (–18, 24). The scale factor is 1 and one-third. The scale factor is 1 and one-fifth. The scale factor is Three-fourths. The coordinates of A are (16, –8). The coordinates of A are (9, –4.5).
Mathematics
2 answers:
nika2105 [10]2 years ago
5 0

Answer:

C is (-18, 24)

Scale factor --> 1 1/3

A is (9, - 4 1/2)  *4 1/2 is also 4.5

<u><em>Brainliest please, I need a few more :D</em></u>

Vladimir [108]2 years ago
3 0

Answer: B, C, and G in other words 2, 3, and 7

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(iii) Find the smallest whole number h such that<br>4704/h<br>is a cube number.<br>​
yan [13]

Answer:

h=588

Step-by-step explanation:

Given the fraction \dfrac{4,704}{h}

Consider its numerator and factor it:

4,704=2^5\cdot 3\cdot 7^2

You cann not take the cube root from 3, 7^2, 2^5, you can only take the cube root from 2^3, then the smallest whole number h such that \dfrac{4,704}{h} is a cube number is

h=2^2\cdot 3\cdot 7^2=4\cdot 3\cdot 49=588

When h=588,

\dfrac{4,704}{588}=8=2^3

6 0
2 years ago
In the figure, angle ZYX is measured in degrees. The area of the shaded sector can be determined using the formula StartFraction
tensa zangetsu [6.8K]

<u>The given options are:</u>

(A)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the area of the circle will yield the area of the sector.

(B)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the circumference of the circle will yield the area of the sector.

(C)the central angle measure of the sector multiplied by the area of the circle will yield the area of the sector.

(D)the central angle measure of the sector multiplied by the circumference of the circle will yield the area of the sector.

Answer:

(A)the central angle measure of the sector divided by the total angle measure of a circle multiplied by the area of the circle will yield the area of the sector.

Step-by-step explanation:

The area of the shaded sector can be determined using the formula:

\frac{m\angle ZYX}{360^\circ} \cdot \pi r^2

m\angle XYZ=$Central angle of XYZ\\\pi r^2$=Area of a Circle

360^\circ =$Total Angle

Therefore, the formula is:

\dfrac{m\angle ZYX}{360^\circ} \cdot \pi r^2\\\text{Area of XYZ}=\dfrac{\text{Cental Angle of XYZ}}{\text{Total Angle}} X \text{Area of the Circle}

Therefore, the formula is best explained by Option A.

7 0
2 years ago
Which function has a simplified base of 4^3√4?
IrinaVladis [17]

Answer:

The function is f(x) = 4(\sqrt[3]{16} )^{2x}.

Step-by-step explanation:

We have to choose from options the exponential function which has a simplified base of 4∛4 i.e. ∛(256).

Now, the exponential function in the option III will be the answer.

The function is f(x) = 4(\sqrt[3]{16} )^{2x}.

So, the base is (\sqrt[3]{16} )^{2} = \sqrt[3]{16^{2}} = \sqrt[3]{256} = 4\sqrt[3]{4}. (Answer)

The general formula of an exponential function is f(x) = a(b)^{x} , where b is called the base of the function.  

4 0
2 years ago
triangle JKL is rotated 270 degrees counterclockwise about the origin to form triangle jkl what is the y-coordinate of point j
IRINA_888 [86]

The y-coordinate of point j' in the image triangle J'K'L' is -x coordinate of point j in the initial triangle JKL.

Step-by-step explanation:

The rule to apply here is that of 90° clockwise about the origin.

This is to say that: rotation 270° counterclockwise about the origin applies the same rule as rotation 90° clockwise about the origin.

In this case, If point j has coordinates (x,y) then after the rotation j' will have coordinates (y,-x)

So the y-coordinate of point j' in the image triangle J'K'L' is -x coordinate of point j in the initial triangle JKL.

Learn more

Rotation about the origin 270°:brainly.com/question/3382538

Keywords : triangle, rotated, origin, counterclockwise,y-coordinate

#LearnwithBrainly

5 0
1 year ago
If 6j-5k =11 and 5j-6k =22, then what is the value of 2j+2k??
dsp73

Answer:

-22

Step-by-step explanation:

6j-5k=11

5j-6k=22

-----------------

5(6j-5k)=5(11)

-6(5j-6k)=-6(22)

-----------------------

30j-25k=55

-30j+36k=-132

-----------------------

11k=-77

k=-77/11

k=-7

6j-5(-7)=11

6j+35=11

6j=11-35

6j=-24

j=-24/6

j=-4

------------------

2j+2k=2(-4)+2(-7)=-8-14=-22

8 0
2 years ago
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