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likoan [24]
1 year ago
14

Peppy Pets charges a flat fee of $15 plus $3 per hour to keep a dog during the day. Happy Hounds charges flat fee of $21 plus $1

per hour. For how many hours is the total fee charged by the companies the same?
Mathematics
2 answers:
Ostrovityanka [42]1 year ago
6 0

Answer:3 hours total

Step-by-step explanation:

15+(3*3)=21+(1*3) which equals out to 24$

Tomtit [17]1 year ago
4 0

Answer:

They both will have a total fee of $24 at 3hrs (15+(3*3)) and (21+(1*3)).

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The dye dilution method is used to measure cardiac output with 3 mg of dye. The dye concentrations, in mg/L, are modeled by c(t)
Lemur [1.5K]

Answer:

Cardiac output:F=0.055 L\s

Step-by-step explanation:

Given : The dye dilution method is used to measure cardiac output with 3 mg of dye.

To Find : Find the cardiac output.

Solution:

Formula of cardiac output:F=\frac{A}{\int\limits^T_0 {c(t)} \, dt} ---1

A = 3 mg

\int\limits^T_0 {c(t)} \, dt =\int\limits^{10}_0 {20te^{-0.06t}} \, dt

Do, integration by parts

[\int{20te^{-0.6t}} \, dt]^{10}_0=[20t\int{e^{-0.6t} \,dt}-\int[\frac{d[20t]}{dt}\int {e^{-0.6t} \, dt]dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20}{0.6}\int {e^{-0.6t} \,dt]^{10}_0

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-20te^{-0.6t}}{0.6}+\frac{20e^{-0.6t}}{(0.6)^2}]^{10}_{0}

[\int{20te^{-0.6t}} \, dt]^{10}_0=[\frac{-200e^{-6}}{0.6}+\frac{20e^{-6}}{(0.6)^2}]+\frac{20}{(0.60^2}

[\int{20te^{-0.6t}} \, dt]^{10}_0=\frac{20(1-e^{-6}}{(0.6)^2}-\frac{200e^{-6}}{0.6}

[\int{20te^{-0.6t}} \, dt]^{10}_0\sim {54.49}

Substitute the value in 1

Cardiac output:F=\frac{3}{54.49}

Cardiac output:F=0.055 L\s

Hence Cardiac output:F=0.055 L\s

4 0
1 year ago
You save $5,000.00 and invest 60% of it in stocks while leaving the rest in a savings account earning a 4.9% APR. The stock incr
Angelina_Jolie [31]

Answer:

5,340

Step-by-step explanation:

Hi there:)

Amount invested in stock

=5000×0.6=3000

Amount invested in a saving account

5000-3000=2000


The stock increases 9% in the first year

3,000×(1+0.09)=3,270

and loses 4% of its value the second year

3,270×(1−0.04)=3,139.2

Amount of a saving account after two years

2,000×(1+0.049)^(2)=2,200.8


the total amount gained during the 2 years

3,139.2+2,200.8=5,340...answer


Hope it helps




8 0
2 years ago
Read 2 more answers
Lian invested an amount of money at an interest rate of 5.2% per year.
Zigmanuir [339]

Answer:

$6500

Step-by-step explanation:

Let the amount of money invested by Lian be $x

Interest rate = 5.2% per year

interest earned in first year will be  5.2% of  amount of money invested by Lian .

(note: since in first year there will be no interest accrued on interest so interest for first year is simple interest )

interest earned in one year if money invested by Lian is $x

= 5.2% of $x  (1)

But , it is given in one year  she received interest of 338 dollars

so, 338 dollars must be equal to 5.2% of $x

equating $338 with  5.2% of $x  , we have

5.2% of x  = 338

=> (5.2/100) * x = 338

=>5.2 x = 338*100

=> x = 33800/5.2 = 6500.

Thus,  amount of money Lian invested is $6500.

7 0
1 year ago
A cell tower is located 3 miles east and 4 miles north of the center of a small town. The cell tower has a coverage radius of 3
butalik [34]

Answer:

The answer is below

Step-by-step explanation:

A cell tower is located 3 miles east and 4 miles north of the center of a small town. The cell tower has a coverage radius of 3 miles.

a) Start by drawing a diagram of this situation. Your diagram might include a coordinate plane, the cell tower, and a circle representing the cell tower's coverage boundary.

a) A house is located 5 miles north of the center of the town and is to the east of the cell tower. If the house lies on the boundary of the cell tower's coverage, how far east of the center of the town is the house?

Answer:

Let the center of the town represent the origin (0,0). Also 1 unit = 1 mile. Since the cell tower is located 3 miles east and 4 miles north of the center of a small town, it is represented by A(3, 4)

The cell tower has a coverage of radius 3 miles. This can be represented by a circle with equation:

(x - a)² + (y - b)² = r². where (a,b) is the center of the circle and r is the radius. Hence:

(x - 3)² + (y - 4)² = 3²

(x - 3)² + (y - 4)² = 9

The diagram is drawn using geogebra.

b) The house is 5 miles north. It can be represented by y = 5 line.

To find the distance east of the house we have to substitute y = 5 and solve for x, hence:

(x - 3)² + (y - 4)² = 9

(x - 3)² + (5 - 4)² = 9

(x - 3)² + 1 = 9

(x - 3)² = 8

(x - 3) = √8

x - 3 = ±2.83

x = 3 ± 2.83

x = 5.83 or 1.83

Since it is to the east to the cell tower, hence x = 5.83.

Therefore the house is located 5.83 miles to the east of the cell tower

8 0
2 years ago
You walk 2 miles from your house to the park and 4.5 miles from the park to the lake. Then you return home along a straight path
pshichka [43]
If they took the same route home itll be 13 miles
8 0
1 year ago
Read 2 more answers
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