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Svet_ta [14]
2 years ago
7

(1 Convert the integral below to polar coordinates and evaluate the integral. ∫4/2√0∫16−y2√yxydxdy∫04/2∫y16−y2xydxdy Instruction

s: Please enter the integrand in the first answer box, typing theta for θθ. Depending on the order of integration you choose, enter dr and dtheta in either order into the second and third answer boxes with only one dr or dtheta in each box. Then, enter the limits of integration and evaluate the integral to find the volume. ∫BA∫DC∫AB∫CD =_____A = _______B = _______C = _______D =_______Volume =_______

Mathematics
1 answer:
Tanzania [10]2 years ago
4 0

Answer:

A = 0

B = π/4

C = 0

D = 4

Volume = 16

Step-by-step explanation:

∫BA∫DC∫AB∫CD is shown in the picture attached

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Which hyperbola has one focus point in common with the hyperbola (y+11)^2/(15^2)-(x-7)^2/(8^2)=1
irina [24]
\bf \textit{hyperbolas, vertical traverse axis }\\\\
\cfrac{(y-{{ k}})^2}{{{ a}}^2}-\cfrac{(x-{{ h}})^2}{{{ b}}^2}=1
\qquad 
\begin{cases}
center\ ({{ h}},{{ k}})\\
vertices\ ({{ h}}, {{ k}}\pm a)
\end{cases}\\\\
-------------------------------\\\\
\cfrac{(y+11)^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\implies \cfrac{(y-(-11))^2}{15^2}-\cfrac{(x-7)^2}{8^2}=1\\\\
-------------------------------\\\\
c=\textit{distance from the center to either foci}\\\\
c=\sqrt{a^2+b^2}\implies c=\sqrt{15^2+8^2}\implies \boxed{c=17}

now, if you notice, the positive fraction, is the one with the "y" variable, and that simply means, the hyperbola traverse axis is over the y-axis, so it more or less looks like the picture below.

now, from the hyperbola form, we can see the center is at (7, -11), and that the "c" distance is 17.

so, from -11 over the y-axis, we move Up and Down 17 units to get the foci, which will put them at (7, -11-17) or (7, -28) and (7 , -11+17) or (7, 6)

5 0
2 years ago
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Round to the nearest benchmark fraction 5/9
Stells [14]
1/2 because 5/9 is equivalent to 10/18. Half of 18 is 9 and 10 is close to 9 so the nearest benchmark fraction you should round to is 1/2. Hope this helps you!
5 0
2 years ago
During the 2015-16 NBA season, J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 . Assume th
ser-zykov [4K]

Answer: 0.5898

Step-by-step explanation:

Given :  J.J. Redick of the Los Angeles Clippers had a free throw shooting percentage of 0.901 .

We assume that,

The probability that .J. Redick makes any given free throw =0.901  (1)

Free throws are independent.

So it is a binomial distribution .

Using binomial probability formula, the probability of getting success in x trials :

P(X=x)^nC_xp^x(1-p)^{n-x}

, where n= total trials

p= probability of getting in each trial.

Let x be binomial variable that represents the number of a=makes.

n= 14

p= 0.901     (from (1))

The probability that he makes at least 13 of them will be :-

P(x\geq13)=P(x=13)+P(x=14)

=^{14}C_{13}(0.901)^{13}(1-0.901)^1+^{14}C_{14}(0.901)^{14}(1-0.901)^0\\\\=(14)(0.901)^{13}(0.099)+(1)(0.901)^{14}\ \ [\because\ ^nC_n=1\ \&\ ^nC_{n-1}=n ]\\\\\approx0.3574+0.2324=0.5898

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5 0
2 years ago
Jose wants to start a restaurant and is writing a business proposal. His rent is $1,000 per month. The monthly operating costs a
Harman [31]

Answer:

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Given Jose wants his monthly sales revenue, x, to be 4 times greater than the operating costs

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R =  4( 1000 + w+ k) + ( 1000 + w+ k)

R =  5( 1000 + w+ k)

Thus, revenue should be  5( 1000 + w+ k).

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Maria has 14 pencils, Ted has 9 pencils, Tom has 12 pencils, Lucinda has 13 pencils, and Jumana has 12 pencils. How can they red
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5 people.

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