Answer:
jump discontinuity at x = 0; point discontinuities at x = –2 and x = 8
Step-by-step explanation:
From the graph we can see that there is a whole in the graph at x=-2.
This is referred to as a point discontinuity.
Similarly, there is point discontinuity at x=8.
We can see that both one sided limits at these points are equal but the function is not defined at these points.
At x=0, there is a jump discontinuity. Both one-sided limits exist but are not equal.
Answer:
Not necessarily, because this wasn't an experiment.
Step-by-step explanation:
Answer:
2.6
Step-by-step explanation:
just put one part of the equation in y1 and the other in y2 and hit 2nd trace 5 an hit enter 4 times
then it will bring a graph hit enter 3 time again and it will show u the answer at the bottom left
