First, you divide 58 bars by 4. The answer will be 14 boxes with 2 bars remaining in the box.
(a) Data with the eight day's measurement.
Raw data: [60,58,64,64,68,50,57,82],
Sorted data: [50,57,58,60,64,64,68,82]
Sample size = 8 (even)
mean = 62.875
median = (60+64)/2 = 62
1st quartile = (57+58)/2 = 57.5
3rd quartile = (64+68)/2 = 66
IQR = 66 - 57.5 = 8.5
(b) Data without the eight day's measurement.
Raw data: [60,58,64,64,68,50,57]
Sorted data: [50,57,58,60,64,64,68]
Sample size = 7 (odd)
mean = 60.143
median = 60
1st quartile = 57
3rd quartile = 64
IQR = 64 -57 = 7
Answers:
1. The average is the same with or without the 8th day's data. FALSE
2. The median is the same with or without the 8th day's data. FALSE
3. The IQR decreases when the 8th day is included. FALSE
4. The IQR increases when the 8th day is included. TRUE
5. The median is higher when the 8th day is included. TRUE
<span>Juan, because 186/140 is more than any of the other percentage increases</span>
Given:
Area of rectangle = 
Width of the rectangle is equal to the greatest common monomial factor of 
.
To find:
Length and width of the rectangle.
Solution:
Width of the rectangle is equal to the greatest common monomial factor of is
Now,
So, width of the rectangle is 
.
Area of rectangle is
Taking out GCF, we get
We know that, area of a rectangle is the product of its length and width.
Since, width of the rectangle is , therefore length of the rectangle is 
.
Answer:
Revenue = 5( 1000 + w+ k)
Step-by-step explanation:
Lets calculate expenses first
rent = $1000
wages = w
overhead cost = k
Total cost = rent + wage+ overhead
Total cost = 1000 + w+ k
Given Jose wants his monthly sales revenue, x, to be 4 times greater than the operating costs
Let revenue be R
Thus, putting the statement mathematically
revenue - total cost = 4 * operating cost
R - ( 1000 + w+ k) = 4( 1000 + w+ k)
R = 4( 1000 + w+ k) + ( 1000 + w+ k)
R = 5( 1000 + w+ k)
Thus, revenue should be 5( 1000 + w+ k).
