Answer: no
Step-by-step explanation: see attachment
The probability of the pointer lands on red(R) both spin =
Step-by-step explanation:
Given,
The number of parts = 6
The pointer is spun twice.
To find the probability of the pointer lands on red(R) both spin.
Formula
Probability of an event = number of required outcomes ÷ the total number of outcomes.
P(A and B) = P(A)×P(B)
Now,
For one spin,
A = RED comes.
For second spin,
B = RED comes
So,
P(A) =
and P(B) =
Then,
P(A and B) =
×
=
Hence, the probability of the pointer lands on red(R) both spin =
Answer: 0.0476
Step-by-step explanation:
Given : Two friends and 5 other people compete with each other for first and second chair in an orchestra.
Total people in this competition= 2+5=7
By permutation , Number of ways to arrange 7 people= 7!
Also, number of ways for two friends end up as first and second chair together= 2 × 5! [ 2 ways to arrange friends on first and second chair and 5! ways to arrange others]
I.e. Required probability = 

Hence, the probability that the two friends end up as first and second chair together = 0.0476