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Daniel [21]
2 years ago
10

Two friends compete with each other and five other, equally good, violinists for first and second chair in an orchestra, in a bl

ind competition What is the probability that the two friends end up as first and second chair together?
Mathematics
1 answer:
Darina [25.2K]2 years ago
4 0

Answer: 0.0476

Step-by-step explanation:

Given : Two friends and 5 other people compete with each other for first and second chair in an orchestra.

Total people in this competition= 2+5=7

By permutation , Number of ways to arrange 7 people= 7!

Also, number of ways for two friends end up as first and second chair together= 2 × 5!   [ 2 ways to arrange friends on first and second chair and 5! ways to arrange others]

I.e. Required probability = \dfrac{2\times5!}{7!}

=\dfrac{2!\times5!}{7\times6\times5!}\\\\=\dfrac{1}{7\times3}\\\\=\dfrac{1}{21}\\\\=0.0476

Hence, the probability that the two friends end up as first and second chair together = 0.0476

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