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Marrrta [24]
2 years ago
8

Lionel is planning a one-day outing.

Mathematics
2 answers:
pychu [463]2 years ago
6 0

Answer:

Option B - y=5x+40 and  y=3x+60

Step-by-step explanation:

Given : The Thrill amusement park charges an entry fee of $40 and an additional $5 per ride, x. The Splash water park charges an entry fee of $60 and an additional $3 per ride, x.

To find : Which system of equations could be used to determine the solution where the cost per ride of the two amusement parks, y, is the same?

Solution :

Let x be the number of rides and

y be the cost per ride.

According to question,

The Thrill amusement park charges an entry fee of $40 and an additional $5 per ride.

The equation form is y=40+5x

The Splash water park charges an entry fee of $60 and an additional $3 per ride.

The equation form is y=60+3x

Therefore, The required system of equations form are

y=5x+40 and  y=3x+60

So,Option B is correct.

Lelechka [254]2 years ago
4 0

Answer:

y= 40+5x

y= 60+3x

Step-by-step explanation:

Thrill amusement park

Entry fee = $40

Cost of 1 ride = $5

Let x be teh no. of rides

Cost of x rides = 5x

So, Total cost = 40+5x

Let the total cost be y

So,Total cost =y= 40+5x

Splash water park

Entry fee = $60

Cost of 1 ride = $3

Let x be the no. of rides

Cost of x rides = 3x

So, Total cost = 60+3x

Let the total cost be y

So,Total cost =y= 60+3x

So, system of equations could be used to determine the solution where the cost per ride of the two amusement parks, y, is the same is :

y= 40+5x

y= 60+3x

Hence Option B is true .

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Answer:

Step-by-step explanation:

Corresponding fuel efficiencies of manufacturer A's car and manufacturer B's car form matched pairs.

The data for the test are the differences between the efficiencies of manufacturer A's car and manufacturer B's car

μd = fuel efficiency of manufacturer A's car minus the​ fuel efficiency of manufacturer B's car.

A B diff

32 28 4

27 22 5

26 27 - 1

26 24 2

25 24 1

29 25 4

31 28 3

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Sample mean, xd

= (4 + 5 - 1 + 2 + 1 + 4 + 3 - 2)/8 = 2

xd = 2

Standard deviation = √(summation(x - mean)²/n

n = 8

Summation(x - mean)² = (4 - 2)^2 + (5 - 2)^2 + (- 1 - 2)^2 + (2 - 2)^2 + (1 - 2)^2 + (4 - 2)^2 + (3 - 2)^2 + (- 2 - 2)^2 = 44

Standard deviation = √(44/8

sd = 2.35

For the null hypothesis

H0: μd = 0

For the alternative hypothesis

H1: μd ≠ 0

This is a two tailed test and the distribution is a students t. Therefore, degree of freedom, df = n - 1 = 8 - 1 = 7

2) The formula for determining the test statistic is

t = (xd - μd)/(sd/√n)

t = (2 - 0)/(2.35/√8)

t = 2.41

We would determine the probability value by using the t test calculator.

p = 0.047

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6 0
2 years ago
A scientist poured 1.6 x 103 milliliters of water into a container that already had 2.8 x 104 milliliters of salt water and 9.4
Tomtit [17]

This question is incomplete

Complete Question

A scientist poured 1.6 x 10³ milliliters of water into a container that already had 2.8 x 10⁴ milliliters of salt water and 9.4 x 10³ milliliters of sugar water. How many milliliters of liquid were in the container?

A.1.7 x 10⁴ milliliters

B.3.58 x 10⁴ milliliters

C.3.74 x 10⁴ milliliters

D.3.9 x 10⁴ milliliters

Answer:

C. 3.74 x 10⁴ milliliters

Step-by-step explanation:

The milliliters of liquid that WERE in the container = The milliliters of liquid that were in the container before adding 1.6 x 10³ milliliters of water

This equals to:

2.8 x 10⁴ milliliters of salt water and 9.4 x 10³ milliliters of sugar water.

Hence:

2.8 x 10⁴ milliliters of salt water + 9.4 x 10³ milliliters of sugar water

= (2.8 × 10⁴) + (9.4 × 10³)

= 37400

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4 0
2 years ago
Use the graphing calculator to locate the solutions of this system of equations:
777dan777 [17]
Hello,

y=(x-2)²-15
y=5x-1

==> 5x-1=x²-4x+4-15
==> x²-9x-10=0
Δ=9²+4*10=11²
x=(9+11)/2 or x=(9-11)/2
==>(x=10 and y=5*10-1=49) or (x=-1 and y=5*(-1)-1=-6)

1) A (-1,-6)
2) C (10,49)

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2 years ago
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Answer:

When you are adding or subtracting a negative fraction, you usually want to consider the numerator as negative. The method is just the same, except now you may need to add negative or positive numerators. The LCM of and is . To add the fractions with unlike denominators, rename the fractions with a common denominator.

Step-by-step explanation:


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