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Simora [160]
1 year ago
8

Ella purchased a game that was on sale for 12% off. The sales tax in her county is 6%. Let y represent the original price of the

game. Write an expression that can be used to determine the final cost of the game.
A y − 0.12y

B 0.06(0.88y)

C 1.06(0.88y)

D y − 0.88y + 0.06y
Mathematics
1 answer:
klio [65]1 year ago
4 0

Answer:

The expression that can be used to determine the final cost of the game is

1.06(0.88 y) ⇒ (C)

Step-by-step explanation:

  • If the price of an item is discounted, that mean its new price will be less its initial price
  • The taxes on item, makes its new price greater than the initial price because tax is add

Let us solve the problem

∵ Ella purchased a game that was on sale for 12% off

→ That means the new price will (100% - 12%) of the initial price

∵ y represented the initial price of the game

→ Multiply y by (100% - 12%) to get the new price

∴ The new price = y (100% - 12%)

∴ The new price = y (88%)

→ Change 88% to normal number by divide it by 100

∴ The new price = y (\frac{88}{100})

∴ The new price = 0.88 y

∵ The sales tax in her county is 6%

→ That means the final cost will be (100% + 6%) of 0.88 y

∴ The final cost = (100% + 6%) × (0.88 y)

∴ The final cost = 106% × (0.88 y)

→ Change 106% to normal number by divide it by 100

∴ The final cost = \frac{106}{100} × (0.88 y)

∴ The final cost = 1.06(0.88 y)

The expression that can be used to determine the final cost of the game is 1.06(0.88 y)

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Answer:

number of successes

                 k  =  235

number of failure

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The   criteria are met    

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What this mean is that for N number of times the survey is carried out that the which sample proportion obtain will differ from  the true population proportion will not  more than 4.4%

Ci  

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D

   This 95% confidence interval  mean that the the chance of the true    population proportion of those that are happy to be exist within the upper   and the lower limit  is  95%

E

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 Yes our result would support the claim because

            \frac{1}{3 } \ of  N    < \frac{1}{2}  (50\%) \ of \  N  , \ Where\ N \ is \ the \  population\ size

Step-by-step explanation:

From the question we are told that

     The sample size is  n  = 500

     The sample proportion is  \r p  =  0.47

 

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             k  =  n  *  \r p

substituting values

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Generally the number of failure  is mathematical represented as

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substituting values

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substituting values

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The lower limit of the   95% confidence interval is  v =  0.426 =  42.6 \%

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Yes our result would support the claim because

            \frac{1}{3 }  < \frac{1}{2}  (50\%)

 

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