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kumpel [21]
2 years ago
9

Regina takes yoga classes 2 days a week at the community center.The cost for the classes is $72,and Regina pays an additional on

e-time fee of $12 to rent the yoga equipment used in class.The classes run for 6 weeks.The local gym offers the same yoga program,including equipment, for $8a class.Is Regina paying more or less than what the local gym charges for yoga classes?
What is a good plan for solving the problem?Explain your strategy.




Is Regina paying more or less for yoga classes at the community center than what the local gym charges for the same program?Show how you calculated accurately.






Regina also pays $4 to take one aerobics class a week.How much money does Regina spend each week on exercise classes?
Mathematics
2 answers:
miv72 [106K]2 years ago
8 0
I am wanting to get The highest rank
Anika [276]2 years ago
8 0

Answer:

“)

Step-by-step explanation: :/










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Quadrilateral ABCD in the figure below represents a scaled-down model of a walkway around a historic site. Quadrilateral EFGH re
prisoha [69]

Answer:

<em>165ft</em>

Step-by-step explanation:

Ratio of actual walkway and a model is :

60  ( Ft ) : 15 ( in)  or : 15 : 1

EF = 60 Ft,

FG = 30 Ft,

GH = 30 Ft,

HE = 45 Ft.

60 + 30 + 30 + 45 = 165 Ft



8 0
2 years ago
Read 2 more answers
How many 5-digit numbers are there that are divisible by either 45 or 60 but are not divisible by 90?
o-na [289]

Answer:

2500 numbers

Step-by-step explanation:

Problem;

 Solving for the number of 5-digit numbers divisible either by 45 or 60 but not divisible by 90;

 Let us approach this in a step wise manner;

  5 -digits numbers ranges from 10,000 to 99,999

To solve this problem, let us find the number of digits that are divisible by 45;  

  the first number divisible by 45 within this range is 10035

   the last number divisible by 45 in this range is 99990

    increment is 45

The total number in this range is:

           \frac{last number - first number}{increment}  + 1  = \frac{99990 - 10035}{45}  + 1

                                                      =  2000 numbers

To solve this problem, let us find the number of digits that are divisible by 60;  

  the first number divisible by 60 within this range is 10020

   the last number divisible by  in this range is 99960

    increment is 60

\frac{99990 - 10080 }{90}

The total number in this range is:

               \frac{last number - first number}{increment}  + 1  = \frac{99960 - 10020}{60}  + 1  

                                                         =  1500 numbers

To solve this problem, let us find the number of digits that are divisible by 90;  

  the first number divisible by 90 within this range is 10080

   the last number divisible by  in this range is 99990

    increment is 90

The total number in this range is:

         \frac{last number - first number}{increment} + 1  = \frac{99990 - 10080}{90} + 1

                                                  = 1000 numbers

Now solution:

  Number of 5 digits  = number of 45  + number of 60 - number of 90

                                       = 2000 + 1500  - 1000

                                        = 2500 numbers

3 0
2 years ago
If 1/6x+2/3y=8 what is the value of 2x+8y
Romashka-Z-Leto [24]

Answer: 96

Step-by-step explanation:

Simply multiply the first question by 12 to get 2x+8y=96

<em>Hope it helps <3</em>

7 0
2 years ago
What is the circumference of this circle, in millimeters? use 22/7 for pi<br><br> r = 49
ICE Princess25 [194]
Circumference=2\pi r=2\times \dfrac{22}{7} \times 49 = \boxed{308 \text{ mm}}
7 0
2 years ago
Read 2 more answers
Mr. Ortiz is a driving instructor. Of his students, 23 have taken the driver's test and 17 of them have passed
adelina 88 [10]

Answer:7

Step-by-step explanation:

3 0
2 years ago
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