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2 years ago

Which correctly describes a cross section of the cube below? Check all that apply.

Mathematics

2 answers:

dmitriy555 [2]2 years ago

7 0

Answer:

A cross section parallel to the base is a square measuring 4 cm by 4 cm.

A cross section perpendicular to the base through the midpoints of opposite sides is a square measuring 4 cm by 4 cm.

A cross section that passes through the entire bottom front edge and the entire top back edge is a rectangle measuring 4 cm by greater than 4 cm.

Step-by-step explanation:

Cross sections parallel and Perpendicular to the base are squares 4 × 4

The diagonal cross section will be a rectangle with base 4 and height

sqrt(4² + 4²) = 4sqrt(2) > 4

wolverine [178]2 years ago

4 0

Answer:

B,D, and E

Step-by-step explanation:

A cross section parallel to the base is a rectangle measuring 4 cm by greater than 4 cm.

A cross section perpendicular to the base through the midpoints of opposite sides is a square measuring 4 cm by 4 cm.

A cross section that passes through the entire bottom front edge and the entire top back edge is a rectangle measuring 4 cm by greater than 4 cm.

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The number of nails in the bucket is 50 less than twice a number of screws. Together, there are 400 fasteners in the bucket. How

kati45 [8]

Answer:

There are 250 nails and 150 screws in the bucket.

Step-by-step explanation:

Let Number of nails in bucket be x.

Also Let number of screws in the bucket be y.

Together, there are 400 fasteners in the bucket.

Hence the equation can be framed as;

$x+y = 400 \ \ \ \ equation \ 1$

Also Given:

The number of nails in the bucket is 50 less than twice a number of screws.

Hence the equation can be framed as;

$x= 2y -50$

Substituting the value of x in equation 1 we get;

$x+y=400\\2y-50+y=400\\3y=400+50\\3y=450\\y= \frac{450}{3}=150$

Now we have value of y we will substitute in equation 1 we get;

$x+y =400\\x+150 =400\\x =400-150\\x=250$

Hence there are 250 nails and 150 screws in the bucket.

3 0

2 years ago

Tyler reads 2/15 of a book on Monday, 1/3 of it on tuesday, 2/9 of it on Wednesday, and 3/4 of the remainder on thus day. If he

kykrilka [37]

The number of pages in the book is 180

<u>Explanation:</u>

The first thing we should do is to convert these fractions to percentage

$Monday = \frac{2}{15} X 100 = 13.33\\\\Tuesday = \frac{1}{3} X 100 = 33.33%\\\\\\Wednesday = \frac{2}{9} X 100 = 22.22%\\\\\\\\$

3/4 of the remainder on thursday:

Thursday: (100 - (13.33 + 33.33 + 22.22) * (3/4) = 23.33%

he still has 14 pages left to read on friday

Friday: [100 - (13.33 + 33.33 + 22.22) ] - 23.33 = 7.77%

Which means that 14 pages represent 7.77% of the book.

Therefore the number of pages of the book is given by:

$=\frac{100}{7.77} X 14\\\\= 180$

Therefore, number of pages in the book is 180

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2 years ago

David can proofread15 reports in an hour while Armando can proofread 37reports in an hour. If they have 400 reports to proofread

ycow [4]

Together, it would take them 6 hours

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2 years ago

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Trapezoid EFGH has coordinates E(−3, 4) , F(1, 4), G(3, 1) , and H(−5, 1) . Trapezoid E'F'G'H' has coordinates E′(−12, 16) , F′(

julia-pushkina [17]

I believe that the answer would be C

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2 years ago

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△ABC has vertices A(−1, 6), B(2, 10), and C(7, −2) . Find the measure of each angle of the triangle. Round decimal answers to th

kolbaska11 [484]

Answer:

<A = 90°, <B = 71.6° <C = 18.4°

Step-by-step explanation:

Given the vertices of a △ABC to be A(−1, 6), B(2, 10), and C(7, −2)

Before we can get each angle of the triangle, we need to get its sides first.

Using the formula fie finding the distance between two points

D = √(x2-x1)²+(y2-y1)²

For side AB:

Given A(−1, 6), B(2, 10)

AB = √{2-(-1)}²+(10-6)²

AB =√3²+4²

AB = √25

AB = 5

For side AC:

Given A(-1,6) and C(7, −2)

AC = √{7-(-1)}²+(-2-6)²

AC = √8²+8²

AC = √128

AC = √64×2

AC = 8√2

For side BC:

Given B(2,10) and C(7, −2)

BC = √(7-2)²+(-2-10)²

BC = √5²+12²

BC = √25+144

BC = √169

BC = 13

First we need to get theta using cosine rule

|AC|² = |AB|+|BC| - 2|AB||AC| cos theta

(8√2)² = 5²+13²-2(5)(13)cos theta

128 = 169-130costheta

128-169 = -130costheta

-41= -130costheta

Costheta = -41/-130

Cos theta = 0.315

theta = arccos 0.315

theta = 71.64°

<B = 71.6°

Using sine rule to get <A,

BC/sin A = AC/sinB

13/sinA = 8√2/sin71.6°

8√2sinA = 13sin71.6°

SinA = 12.34/8√2

SinA = 1.09°

A = arcsin1

<A = 90.0°

<C = 180°-(71.6+90)

< C = 180-161.6

<C = 18.4°

3 0

2 years ago