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EastWind [94]
1 year ago
15

Formulate the indicated conclusion in nontechnical terms. Be sure to address the original claim. The foundation chair for a hosp

ital claims that the mean number of filled overnight beds is over​ 523, and he is therefore justified starting a funding campaign to add a wing to the hospital. Assuming that a hypothesis test of the claim has been conducted and that the conclusion is failure to reject the null​ hypothesis, state the conclusion in nontechnical terms
Mathematics
1 answer:
slavikrds [6]1 year ago
6 0

Answer:

For this case we want to test if the mean number of filled overnight beds is over​ 523. If X represent our random variable "number of filled overnight beds", the system of hypothesis are:

Null Hypothesis: \mu \leq 523

Alternative hypothesis: \mu > 523

And for this case after conduct the test is FAIL to reject the null hypothesis. So then we can conclude that the claim that the number of filled overnight beds is over​ 523 is not statistically supported

Step-by-step explanation:

Previous concepts

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".  

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".

Solution to the problem

For this case we want to test if the mean number of filled overnight beds is over​ 523. If X represent our random variable "number of filled overnight beds", the system of hypothesis are:

Null Hypothesis: \mu \leq 523

Alternative hypothesis: \mu > 523

And for this case after conduct the test is FAIL to reject the null hypothesis. So then we can conclude that the claim that the number of filled overnight beds is over​ 523 is not statistically supported

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A project’s critical path is composed of activities A (variance .33), B (variance .67), C (variance .33), and D (variance .17).
julia-pushkina [17]

Answer:

The standard deviation on the critical path = 0.834

Step-by-step explanation:

Variance of activity A (V_{1}) = 0.33

Variance of activity B (V_{2}) = 0.67

Variance of activity C (V_{3}) = 0.33

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Thus the standard deviation on the critical path (\alpha ^{2}) = V_{1} ^{2} + V^2_{2} +  V^2_{3} + V^2_{4}

                                                                             \alpha ^{2}  = 0.33^{2} + 0.67^{2} + 0.33^{2} + 0.17^{2}

                                                                             \alpha ^{2} = 0.6956

                                                                             \alpha = 0.834

The standard deviation on the critical path = 0.834

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The zoo needed to raise $25,000. Zoo officials planned a dinner/dance event and charged $300 per couple. What is the fewest numb
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Answer:

expression a

Step-by-step explanation:

The given expression is 15+0.25(d−1).

let suppose,

15 = a

0.25(d−1) = b

we get  a + b

It clearly indicates the given expression is sum of two entities, we can exclude  option b and option d.

Now we are left with option a and c, for that we have to evaluate the term b

b = 0.25(d−1) <u>that is the additional amount after d days</u>

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The <em><u>correct answer</u></em> is:

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The initial velocity is 50, and the initial height is 3; this gives us the equation

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