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posledela
2 years ago
6

A market analyst is developing a regression model to predict monthly household expenditures on groceries as a function of family

size, household income, and household neighborhood (urban, suburban, and rural). The response variable in this model is _____.
Mathematics
1 answer:
notka56 [123]2 years ago
8 0

Answer:

Monthly household expenditures on groceries

Step-by-step explanation:

The response variable is the one for which measurements are desired and that depends on other variables.

In this case, family size, household income, and household neighborhood are independent variables, while the response variable is the monthly household expenditures on groceries.

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A toddler is allowed to dress himself on Mondays, Wednesdays, and Fridays. For each of his shirt, pants, and shoes, he is equall
avanturin [10]

Answer:

0.0286 = 2.86% probability that today is Monday.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Dressed correctly

Event B: Monday

Probability of being dressed correctly:

100% = 1 out of 4/7(mom dresses).

(0.5)^3 = 0.125 out of 3/7(toddler dresses himself). So

P(A) = 0.125\frac{3}{7} + \frac{4}{7} = \frac{0.125*3 + 4}{7} = \frac{4.375}{7} = 0.625

Probability of being dressed correctly and being Monday:

The toddler dresses himself on Monday, so (0.5)^3 = 0.125 probability of him being dressed correctly, 1/7 probability of being Monday, so:

P(A \cap B) = 0.125\frac{1}{7} = 0.0179

What is the probability that today is Monday?

P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.0179}{0.625} = 0.0286

0.0286 = 2.86% probability that today is Monday.

4 0
2 years ago
Mark and Bonnie both make $11 per hour working for their parents. If they combine their efforts and work for the same amount of
Mademuasel [1]
To answer this we would need the expressions given.
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In a recent survey ,5 out of every 8 middle school students use a computer to complete school projects .franklin middle school h
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A company wants to establish that the mean life of its batteries, when used in a wireless mouse, is over 183 days. The data will
enyata [817]

Answer:

a) Null and alternative hypotheses are:

H_{0}: mu=183 days

H_{a}: mu>183 days

b) If the true mean is 190 days, Type II error can be made.

Step-by-step explanation:

Let mu be the mean life of the batteries of the company when it is used in a wireless mouse

Null and alternative hypotheses are:

H_{0}: mu=183 days

H_{a}: mu>183 days

Type II error happens if we fail to reject the null hypothesis, when actually the alternative hypothesis is true.

That is if we conclude that mean life of the batteries of the company when it is used in a wireless mouse is at most 183 days, but actually mean life is 190 hours, we make a Type II error.

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2 years ago
ΔABC is an equilateral triangle. m∠A = (3x - 12)°. Solve for x. A) 14 B) 19 C) 20 D) 24
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Answer:

c is the answer

Step-by-step explanation:

hope it is correct tho

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