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sergey [27]
2 years ago
13

a school district requires all graduating seniors to take a mathematics test. This year, the rest scores were approximately norm

ally distributed for the 1208 graduating seniors. This mean score on the test was a 74 and the standard deviation was 11. what percent of the graduating seniors had a test above 85? Express your answers to the nearest percent.
Mathematics
1 answer:
Klio2033 [76]2 years ago
3 0
A score of 85 would be 1 standard deviation from the mean, 74.  Using the 68-95-99.7 rule, we know that 68% of normally distributed data falls within 1 standard deviation of the mean.  This means that 100%-68% = 32% of the data is either higher or lower.  32/2 = 16% of the data will be higher than 1 standard deviation from the mean and 16% of the data will be lower than 1 standard deviation from the mean.  This means that 16% of the graduating seniors should have a score above 85%.
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= 35x + \frac{x \times 7.5}{100} [35 + 34 + 33 + ......... + 1]

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{Since sum of n natural numbers is given by \frac{1}{2} (n)(n + 1)}

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= 82.25x

Now, given that the final amount will be i million dollars = $1000000

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Therefore. I have to invest $12159 per year. (Answer)

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