Answer: width = 5 units
Step-by-step explanation:
Let L represent the length of the rectangle.
The width of a rectangle is the length minus 2 units. It means that the width of the rectangle is (L - 2) units.
The formula for determining the area of a rectangle is expressed as
Area = length × width
The area of the rectangle is 35 units. It means that
L(L - 2) = 35
L² - 2L = 35
L² - 2L - 35 = 0
L² + 5L - 7L - 35 = 0
L(L + 5) - 7(L + 5) = 0
L - 7 = 0 or L + 5 = 0
L = 7 or L = - 5
Since the length cannot be negative, then
L = 7 units
Width = 7 - 2 = 5 units
Answer:
D) n^6 - 6m^6 + 7mn^5 + 14m^2n^4 -5m^3 n^3
Step-by-step explanation:
The given polynomial is 8mn^5 -2m^6 +5m^2 n^4 - m^3 n^3 + n^6 - 4m^6 + 9m^2n^4 -mn^5 - 4m^3n^3
Now we have to identify the like terms and simplify.
Like terms are nothing but the terms which have the same variables with same powers.
= (8mn^5 - mn^5) -2m^6 - 4m^6 + 5m^2 n^4 + 9m^2 n^4 - m^3n^3 - 4m^3n^3 +n^6
Now combine the like terms
= 7mn^5 - 6m^6 +14m^2 n^4-5m^3n^3 + n^6
It can be written in standard form
= n^6 - 6m^6 + 7mn^5 + 14m^2n^4 -5m^3 n^3
The answer is D)
Hope this will helpful.
Thank you.
Answer:
5.46
Step-by-step explanation:
3.24/5.4 = y/9.1
Answer:
Option B.
Step-by-step explanation:
It is given that ΔSRQ is a right angle triangle, ∠SRQ is right angle.
RT is altitude on side SQ, ST=9, TQ=16 and SR=x.
In ΔSRQ and ΔSTR,
(Reflexive property)
(Right angle)
By AA property of similarity,
Corresponding parts of similar triangles are proportional.
Substitute the given values.
On cross multiplication we get
Taking square root on both sides.
The value of x is 15. Therefore, the correct option is B.
Answer:
AC and OA
Step-by-step explanation:
-A secant is a line connecting two points on the circle.
-Given the square OABC of sides 6cm and a circle of r=5cm and the center of the circle as O, and that the radius of the circle is less than the side of the square:
-The circle passes through OA and OC, but doesn't pass through AB and BC.
Hence, AC and OA are the circle's secants.
