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2 years ago

How many possible outcomes exist when two fair coins are flipped and a three-section spinner is spun?

Mathematics

2 answers:

denis-greek [22]2 years ago

5 0

Answer:

Yeah, like the guy said the answer is 12. I just took it on edg.

Step-by-step explanation:

kodGreya [7K]2 years ago

4 0

Each coin can have the outcomes heads (H) or tails (T).
The spinner can have the outcomes 1, 2, 3.
The total number of outcomes is the product of the individual numbers of outcomes.
2 * 2 * 3 = 12

Here's a way of thinking about it:

The coins can have these four outcomes:
HH
HT
TH
TT
For each of the 4 outcomes of the two coins, there are 3 different outcomes of the spinner, so the total number of possible outcomes is 4 * 3 = 12.

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at what x coordinate would a line whose equation is y=2x-3 intersect a perpendicular line whose y intercept is 17

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Step-by-step explanation:hj

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1 year ago

Students have a choice between taking a test on paper or on the computer. Mrs. Gazi graphed the relationship between the number

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Step-by-step explanation:

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2 years ago

Read 2 more answers

A salesman normally makes a sale (closes) on % of his presentations. Assuming the presentations are independent, find the pro

Tamiku [17]

Answer:

$(a)\ 0.0864$

$(b)\ 0.096$

$(c)\ 0.24$

$(d)\ 0.936$

Step-by-step explanation:

Given

$p \to$ close

$q \to$ fail to close

$p = 60\%$

$p = 0.60$

First, calculate the value of q

Using complement rule

$q = 1 - p$

$q = 1 - 0.60$

$q = 0.40$

So, we have:

$p = 0.60$ and $q = 0.40$

Solving (a): Fails to close on the 4th attempt

This means that he closes the first three attempts. The event is represented as: p p p q

So, we have:

$Pr = p*p*p*q$

$Pr = p^3*q$

$Pr = 0.60^3*0.40$

$Pr = 0.0864$

Solving (b): He closes for the first time on the 3rd attempt

This means that he fails to close the first two attempts. The event is represented as: q q p

So, we have:

$Pr = q * q * p$

$Pr = q^2 * p$

$Pr = 0.40^2 * 0.60$

$Pr = 0.096$

Solving (c): First he closes is his 2nd attempt

This means that he fails to close the first. The event is represented as: q p

So, we have:

$Pr = q * p$

$Pr = 0.40 * 0.60$

$Pr = 0.24$

Solving (d): The first he close is one of his 3 attempts

To do this, we make use of complement rule

The event that he does not close any of his first three attempts is: q q q

The probability is:

$Pr = q*q*q$

$Pr = q^3$

The opposite is that the first he closes is one of the first three

So, we have:

$Pr' = 1- Pr$ --- complement rule

$Pr' = 1- q^3$

$Pr' = 1- 0.40^3$

$Pr' = 1- 0.064$

$Pr' = 0.936$

4 0

2 years ago

Which number line models the expression 1/8-(-3/4)

RideAnS [48]

Answer:

$\frac{7}{8}$

Step-by-step explanation:

Given: $\frac{1}{8}-(\frac{-3}{4} )$

To find: number which represents the expression

Solution:

Integers refers to natural numbers, 0 together with negative of rational numbers.

A rational number is the number of the form $\frac{p}{q}$ where p and q are integers and $q\neq 0$ .

$\frac{1}{8}-(\frac{-3}{4} )=\frac{1}{8}+\frac{3}{4}\\ =\frac{1+6}{8}\\ =\frac{7}{8}$

So, $\frac{7}{8}$ represents $\frac{1}{8}-(\frac{-3}{4} )$

6 0

2 years ago

Given the functions m(x) = 4x − 11 and n(x) = x − 10, solve m[n(x)] and select the correct answer below. (2 points)

Citrus2011 [14]

For this case what we must do is a composition of functions which will be given by:
m (x) = 4x - 11
n (x) = x - 10
We have then:
m [n (x)] = 4 (x - 10) - 11
Rewriting the function:
m [n (x)] = 4x - 40 - 11
m [n (x)] = 4x - 51
Answer:
a. m [n (x)] = 4x - 51

4 0

2 years ago