Answer:
The observed tumor counts for the two populations of mice are:
Type A mice = 10 * 12 = 120 counts
Type B mice = 13 * 12 = 156 counts
Step-by-step explanation:
Since type B mice are related to type A mice and given that type A mice have tumor counts that are approximately Poisson-distributed with a mean of 12, we can then assume that the mean of type A mice tumor count rate is equal to the mean of type B mice tumor count rate.
This is because the Poisson distribution can be used to approximate the the mean and variance of unknown data (type B mice count rate) using known data (type A mice tumor count rate). And the Poisson distribution gives the probability of an occurrence within a specified time interval.
Answer:
992
Step-by-step explanation:
Divide 1000 by 26.
The answer is 38 and some left over. We don't care what the leftover is because it is nearly 0.5 and that means 13 people were left over.
Take the integer value (38) and multiply it by 26. You get 988.
You want there to be 4 left over. 4 + 988 = 992. That's one way of doing the problem.
Answer:
0.24
Step-by-step explanation:
These events are not mutually exclusive; this means they can happen at the same time.
For two events A and B that are not mutually exclusive,
P(A and B) = P(A) * P(B|A)
Let A be the event "over 21 years old" and B be the event "drinks alcohol".
The probability that a student is over 21 years old is 0.3; this is because 30% of the students are over 21 years old.
The probability that a student drinks alcohol given they are over 21 is 0.8.
This gives us
P(A and B) = 0.3(0.8) = 0.24
Answer:
Step-by-step explanation:
Given
Required
Determine the value of T
Multiply both sides by 2
Divide through by 6
