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stiv31 [10]
2 years ago
14

A shop sells three types of boots sales are usually in the ratio of 6:2:3 last month 24 football boots were sold how many boots

altogether were sold last month
Mathematics
1 answer:
Sonja [21]2 years ago
8 0
The three types of boots are sold in the ratio 6:2:3.

This ratio may be written as 6x:2x:3x where x is a variable.
When 24 boots are sold, then
6x + 2x + 3x = 24
11x = 24
x = 24/11 = 2.18

Because we do not have fractional boots, x = 2.
Total boots sold = 6*2 + 2*2 + 3*2 = 12 + 4 + 6 =  22

Answer: 22

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Solve the equation 1 4 (16 + 12x) = 28 by first using the distributive property. The equivalent equation is found by distributin
BARSIC [14]

Answer:

8

Step-by-step explanation:

Given the equation 1/4 (16 + 12x) = 28, to solve this first we open the bracket using the distributive property. According to this property, given A, B and C then:

A(B+C ) = AB+AC

Step 1:

1/4 (16 + 12x) = 28

= 1/4(16)+1/4(12x) = 28

= 4+3x = 28

Step 2:

We move 4 to the other side to have:

3x = 28-4

3x = 24

Step 3:

Divide both sides by 3 to have,:

3x/3 = 24/3

x = 8

The answer is 8

6 0
2 years ago
Read 2 more answers
Find the value of $x$ that maximizes $$f(x) = \log (-20x + 12\sqrt{x}).$$ If there is no maximum value, write "NONE".
kakasveta [241]
The function is written as:
f(x) = log(-20x + 12√x)
To find the maximum value, differentiate the equation in terms of x, then equate it to zero. The solution is as follows.

The formula for differentiation would be:
d(log u)/dx = du/u ln(10)
Thus,
d/dx = (-20 + 6/√x)/(-20x + 12√x)(ln 10) = 0
-20 + 6/√x = 0
6/√x = 20
x = (6/20)² = 9/100

Thus,
f(x) =  log(-20(9/100)+ 12√(9/100)) = 0.2553

<em>The maximum value of the function is 0.2553.</em>
5 0
2 years ago
What is the result of anding 255 and 15?
Tema [17]
The result of adding 255 and 15 is;

255 + 15 = 270


8 0
2 years ago
Solve the inequality. Using a verbal statement, in simplest terms, describe the solution of the inequality. Be sure to include t
rodikova [14]
-2x + 3 > 3(2x - 1)

the inequality sign > means 'greater than'.

First simplify the right side of the equation by distributing the 3 over the parentheses:-

-2x + 3 > 6x - 3

Now add -6x to both sides of the inequality  which gives us
-8x + 3 > -3
Adding -3 to both sides we have
-8x > -6

The next step is to divide  both sides by -8 so x is isolated on the left side and this gives us the solution. However there is a rule with inequalities that if you divide  the variable term by a negative the inequality is flipped. So in this case , greater that (>) becomes  less than (<):-

-8x / -8 < -6/-8

x <  3/4  is your answer.
7 0
2 years ago
Recent homebuyers from a local developer allege that 30% of the houses this developer constructs have some major defect that wil
umka21 [38]

Answer:

3.54% probability of observing at most two defective homes out of a random sample of 20

Step-by-step explanation:

For each house that this developer constructs, there are only two possible outcomes. Either there are some major defect that will require substantial repairs, or there is not. The probability of a house having some major defect that will require substantial repairs is independent of other houses. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

30% of the houses this developer constructs have some major defect that will require substantial repairs.

This means that p = 0.3

If the allegation is correct, what is the probability of observing at most two defective homes out of a random sample of 20

This is P(X \leq 2) when n = 20. So

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{20,0}.(0.3)^{0}.(0.7)^{20} = 0.0008

P(X = 1) = C_{20,1}.(0.3)^{1}.(0.7)^{19} = 0.0068

P(X = 2) = C_{20,2}.(0.3)^{2}.(0.7)^{18} = 0.0278

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0008 + 0.0068 + 0.0278 = 0.0354

3.54% probability of observing at most two defective homes out of a random sample of 20

5 0
2 years ago
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