Answer:
The value of the account in the year 2009 will be $682.
Step-by-step explanation:
The acount's balance, in t years after 1999, can be modeled by the following equation.

In which A(t) is the amount after t years, P is the initial money deposited, and r is the rate of interest.
$330 in an account in the year 1999
This means that 
$590 in the year 2007
2007 is 8 years after 1999, so P(8) = 590.
We use this to find r.




Applying ln to both sides:




Determine the value of the account, to the nearest dollar, in the year 2009.
2009 is 10 years after 1999, so this is A(10).


The value of the account in the year 2009 will be $682.
Answer:
4,2,7
Step-by-step explanation
they are the ones repeating at the end
If the company makes 1 canoe only, then the cost is, the fixed cost plus how much it costs for the 1 canoe, or
180,000 + 1*120
if it makes 2 canoes
180,000 + 2*120
3 canoes 180,000 + 3*120
4canoes 180,000 + 4*120
x canoes 180,000 + x*120
so... we dunno what "x" is, but whatever "x" maybe, the cost ends up as 180,000 + x*120, or 180,000 + 120x
now, let's see the revenue
1 canoe 1 * 240
2 canoes 2*240
3 canoes 3*240
x canoes x*240
so.. whatever "x" maybe, the Revenue is x*240 or 240x
break-even point is when, the amount of expenses and earnings cancel each other out, or, there's no profit, but there's no loss either, same amount that's spent is also earned back
so, the break-even point occurs when Revenue = Cost
180,000 + 120x = 240x <--- solve for "x"
Total Attendence = Mean Attendence × No. of Incidents
= 24,500 × 25
= 612,500.