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2 years ago

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The lithosphere (made of Earth's crust and the very top part of the mantle) is a stiff outer layer of the Earth. Convection in t

he _______ helps move pieces of the lithosphere around.

1 answer:

Ilya [14]2 years ago

6 0

Convection in the <u>Mantle</u> helps move pieces of the lithosphere around.

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Small Sample Mean Problem. The maker of potato chips uses an automated packaging machine to pack its 20-ounce bag of chips. At t

VladimirAG [237]

Answer:

Step-by-step explanation:

3 0

2 years ago

Which table contains only corresponding x-values and y-values where the value of y is one more than the product of x and 2?

Dmitry [639]

Answer:

Option (C)

Step-by-step explanation:

Value of y is more than the product of x and 2.

Equation representing the given condition will be,

y = 2x + 1

Therefore, by substituting the values of x in the equation we can get the table for the input - output values for the equation,

x 0 1 2 3 4

y 1 3 5 7 9

Therefore, table given in the Option (C) will be the correct option.

4 0

2 years ago

Which will result in a difference of squares? (negative 7 x + 4)(negative 7 x + 4) (negative 7 x + 4)(4 minus 7 x) (negative 7 x

nevsk [136]

Answer:

(negative 7 x + 4)(negative 7 x minus 4)

Step-by-step explanation:

Consider two real numbers a and b. A difference of squares involving a and b is usually given as;

$a^{2}-b^{2}$

The difference of the two squares above can be factored to yield;

$(a-b)(a+b)$

This implies that in order to have the difference of squares we must have a product involving the difference and the sum of the numbers.

The expression;

(negative 7 x + 4)(negative 7 x minus 4) can also be written as ( 4 - 7x) ( -4 - 7x)

( 4 - 7x) ( -4 - 7x) = ( 4 - 7x) (-1( 4 + 7x)) = -1 *( 4 - 7x) ( 4 + 7x)

Expanding the last expression yields;

-1 (16 + 28x -28x - 49x^2) = -1 (16 - 49x^2) = 49x^2 - 16 which is in deed a difference of squares

3 0

2 years ago

Read 2 more answers

6.In a sample of 131 women with cosmetic dermatitis from using eye shadow, 12 were diagnosed with a nickel allergy. In a sample

aivan3 [116]

Answer:

a) $0.0916 - 1.96\sqrt{\frac{0.0916(1-0.0916)}{131}}=0.0422$

$0.0916 + 1.96\sqrt{\frac{0.0916(1-0.0916)}{131}}=0.1410$

So then we can conclude that the true proportion of women with cosmetic dermatitis from using eye shadow at 95% of confidence is between (0.0422 and 0.1410)

b) $\hat p = \frac{25}{250}= 0.1$

$0.1 - 1.96\sqrt{\frac{0.1(1-0.1)}{250}}=0.0628$

$0.1 + 1.96\sqrt{\frac{0.1(1-0.1)}{250}}=0.1372$

So then we can conclude that the true proportion of women with cosmetic dermatitis from using mascara at 95% of confidence is between (0.0628 and 0.1372)

c) For this case we see that both confidence intervals contains the value of 0.12 so then we can't conclude that only one group is referenced at the significance level of 0.05 used.

Step-by-step explanation:

Part a

The estimated proportion of women with cosmetic dermatitis from using eye shadow is given by:

$\hat p =\frac{12}{131}= 0.0916$

The confidence interval is at 95% of confidence, our significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical value would be given by:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The confidence interval for the proportion is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

Replacing we got:

$0.0916 - 1.96\sqrt{\frac{0.0916(1-0.0916)}{131}}=0.0422$

$0.0916 + 1.96\sqrt{\frac{0.0916(1-0.0916)}{131}}=0.1410$

So then we can conclude that the true proportion of women with cosmetic dermatitis from using eye shadow at 95% of confidence is between (0.0422 and 0.1410)

Part b: A 95% confidence interval for the women with cosmetic dermatitis from using mascara

$\hat p = \frac{25}{250}= 0.1$

$0.1 - 1.96\sqrt{\frac{0.1(1-0.1)}{250}}=0.0628$

$0.1 + 1.96\sqrt{\frac{0.1(1-0.1)}{250}}=0.1372$

So then we can conclude that the true proportion of women with cosmetic dermatitis from using mascara at 95% of confidence is between (0.0628 and 0.1372)

Part c: Suppose you are informed that the true proportion with a nickel allergy for one of the two groups (eye shadow or mascara) is .12. Can you determine which group is referenced? Explain.

For this case we see that both confidence intervals contains the value of 0.12 so then we can't conclude that only one group is referenced at the significance level of 0.05 used.

7 0

2 years ago

A worker is paid rs. 2130 for 6 days .if his total wage during a month is rs. 9230 find the number of days he worked in the mont

Katyanochek1 [597]

Answer:

26 days

Step-by-step explanation:

If 6 days = rs. 2130

then 1 day = (2130 × 1) ÷ 6

Therefore 1 day = rs 355

For rs. 9230, the number of days he worked:

= 9230 ÷ 355

= 26 days

4 0

2 years ago