Answer:
The sample of sizes 2 and their mean are given below.
Step-by-step explanation:
The population consist of 5 values, S = {1, 3, 4, 4, 6}.
The number of samples of size 2 (without replacement) that can be formed from these 5 values is:

Th formula to compute the mean is:

List the 10 samples and their mean as follows:
<u>Sample</u> <u>Mean</u>
(1, 3) ![\bar x=\frac{1}{2}[1+3]=\frac{4}{2}=2.0](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7B2%7D%5B1%2B3%5D%3D%5Cfrac%7B4%7D%7B2%7D%3D2.0)
(1, 4) ![\bar x=\frac{1}{2}[1+4]=\frac{5}{2}=2.5](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7B2%7D%5B1%2B4%5D%3D%5Cfrac%7B5%7D%7B2%7D%3D2.5)
(1, 4) ![\bar x=\frac{1}{2}[1+4]=\frac{5}{2}=2.5](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7B2%7D%5B1%2B4%5D%3D%5Cfrac%7B5%7D%7B2%7D%3D2.5)
(1, 6) ![\bar x=\frac{1}{2}[1+6]=\frac{7}{2}=3.5](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7B2%7D%5B1%2B6%5D%3D%5Cfrac%7B7%7D%7B2%7D%3D3.5)
(3, 4) ![\bar x=\frac{1}{2}[3+4]=\frac{7}{2}=3.5](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7B2%7D%5B3%2B4%5D%3D%5Cfrac%7B7%7D%7B2%7D%3D3.5)
(3, 4) ![\bar x=\frac{1}{2}[3+4]=\frac{7}{2}=3.5](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7B2%7D%5B3%2B4%5D%3D%5Cfrac%7B7%7D%7B2%7D%3D3.5)
(3, 6) ![\bar x=\frac{1}{2}[3+6]=\frac{9}{2}=4.5](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7B2%7D%5B3%2B6%5D%3D%5Cfrac%7B9%7D%7B2%7D%3D4.5)
(4, 4) ![\bar x=\frac{1}{2}[4+4]=\frac{8}{2}=4.0](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7B2%7D%5B4%2B4%5D%3D%5Cfrac%7B8%7D%7B2%7D%3D4.0)
(4, 6) ![\bar x=\frac{1}{2}[4+6]=\frac{10}{2}=5.0](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7B2%7D%5B4%2B6%5D%3D%5Cfrac%7B10%7D%7B2%7D%3D5.0)
(4, 6) ![\bar x=\frac{1}{2}[4+6]=\frac{10}{2}=5.0](https://tex.z-dn.net/?f=%5Cbar%20x%3D%5Cfrac%7B1%7D%7B2%7D%5B4%2B6%5D%3D%5Cfrac%7B10%7D%7B2%7D%3D5.0)
With the $10 gift card, Jose can buy at most 8 songs
x(the number of songs) less than or equal to 8
To solve the problem, get the
percentage of each test by multiplying the score and the percentage then add it all up:
82 * .25 (highest test grade) + 65* .15 (lowest test grade) +
71*.20 (each test remaining) + 77*.20 (each test remaining) + 92*.20 (homework
grade)
= 20.5 + 9.75 + 14.2 + 15.4 + 18.4 = 78.25 or 78% in whole number
Answer:

Step-by-step explanation:
The only Pythagorean identities are:




Therefore,
is correct as it's one of the pythagorean identities.
I = PRT.....rearrange = I / PR = T
I = 450
R = 7.5%...turn to decimal = 0.075
P = 2400
I / (PR) = T
450 / (2400 * 0.075) = T
450 / 180 = T
2.5 = T...so time is 2.5 years, or 2 1/2 years